Question

嘿，我有点坚持这个查询。使用SQL-server

我在表格中有UNIQUE（date，medId，userId）

我有这张桌子

date       | medId | userId | Quantity
2016-06-10 |   2   |   1    |   28
2016-06-07 |   1   |   1    |   19
2016-06-06 |   1   |   1    |   10

在这种情况下，我希望得到每组medId，userId的最大日期行我会得到

2016-06-10 |   2   |   1    |   28
2016-06-07 |   1   |   1    |   19

提前感谢！

我试过这个

SELECT 
  a.userMedStockDate,
  a.userMedStockMedId, 
  a.userMedStockUserId,
  a.userMedStockQuantity
FROM (SELECT  
        MAX(userMedStockDate) AS userMedStockDate,
        userMedStockQuantity,
        userMedStockUserId,
        userMedStockMedId,
        ROW_NUMBER() OVER (partition by userMedStockMedId,userMedStockUserId 
                           ORDER BY MAX(userMedStockDate) desc) AS rnk
      FROM UserMedStock
      GROUP BY
        userMedStockUserId, 
        userMedStockQuantity,
        userMedStockMedId) a
WHERE a.rnk = 1

[解决]

Answer 1

这应该有效

 select * from 
(
select 
[date] , medId, userId ,Quantity
,row_number() over (partition by medId, userId order by [date] desc) as rowid 
from yourtable
) as x
where rowid = 1

Answer 2

也可以试试这个：

select y.* from 
table1 y inner join 
(
SELECT [Date] = MAX([Date]), medId, userId
  FROM table1
  GROUP BY medId, userId
) x on y.[Date] = x.[Date] and y.medId = x.medId and y.userId = x.userId

Answer 3

我将字段更改为我的实际表格，但这里

IIS

从聚合中按日期获取最新行

3 个答案: