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<td width="580">Text</td>
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循环中给出列表:a = [1, 2, 3, 4 5]
,假设当前项为2,下一项为3.如果某些条件为真,我怎样才能使下一项为2再次,这意味着迭代应该从2再次继续而不是3?
for
输出结果为:
a = [1, 2, 3, 4, 5]
for item in a:
print item
if condition:
do something, and go back to previous iterator
答案 0 :(得分:1)
小心无限循环,它不是Pythonic。
i = 0
a = [1, 2, 3, 4, 5]
hasBeenReset = False
while i < len(a):
if a[i] == 3 and not hasBeenReset:
i = 1
hasBeenReset = True
print(a[i])
i += 1