Question

我有一个提示输入用户名/密码的URL来获取其数据。数据采用XML格式。起初我试图检索这样的数据：

$url = "http://username:password@[ip-address]:8086/connectioncounts?flat";
$xml = simplexml_load_file($url);
print_r($xml);

在搜索完答案后，我想出了这段代码：

$url = "http://[ip-address]:8086/connectioncounts?flat"; 
$ch = curl_init();     
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);  
curl_setopt($ch, CURLOPT_URL, $url);  
curl_setopt($ch, CURLOPT_USERPWD, "username:password");
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$result = curl_exec($ch);  
curl_close($ch);  
echo $result;

我没有在这些尝试中返回任何数据。有人能告诉我我做错了吗？

Answer 1

我觉得网址是重定向的，您可以尝试添加。这将按照URL返回响应。

curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);

Answer 2

您需要通过填充数组中的CURL选项来更改URL中的端口 -

$ch = curl_init(); 

$options = array(CURLOPT_URL => "http://[ip-address]/connectionscounts?flat/<URI>", 
CURLOPT_PORT => "8086", 
CURLOPT_HEADER => "Content-Type:application/xml", 
CURLOPT_USERPWD => "username:password", 
CURLOPT_HTTPAUTH => CURLAUTH_BASIC, 
CURLOPT_RETURNTRANSFER => TRUE 
); 

curl_setopt_array($ch, $options); 
$data = curl_exec($ch); 

$xml = new SimpleXMLElement($data); 
print_r($xml);

PHP使用凭据从URL获取XML

2 个答案: