Question

我的应用程序中的几个类执行相同的操作并具有相同的实例变量：

// one of the many classes I have
// they all load nibs and update the frames of their views
class HelpView: UIView {
    @IBOutlet var view: UIView!

    required init(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)!
        NSBundle.mainBundle().loadNibNamed("HelpView", owner: self, options: nil)
        self.addSubview(self.view)
        self.view.frame = self.bounds
    }
}

我想避免重复的代码，所以我考虑使用超类，以便所有类继承它。

// my new superclass all classes will inherit from
class ReusableView: UIView {
    @IBOutlet var view: UIView! // all subclasses have different views

    required init(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)!

        // every class has a different nib name
        NSBundle.mainBundle().loadNibNamed("Nib name goes here", owner: self, options: nil)
        self.addSubview(self.view)
        self.view.frame = self.bounds
    }
}

问题是view是nil，直到笔尖被加载，因此显然不可能称之为超类＃＆n;方法，因为您传递了一个零对象。我怎么处理这个？

Answer 1

这将有效：

class ReusableView: UIView {

    func getHelperView() -> UIView! {
        preconditionFailure("This method must be overridden") 
    } 

    func getNibName() -> String {
        preconditionFailure("This method must be overridden") 
    }

    required init(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)!

        // every class has a different nib name
        NSBundle.mainBundle().loadNibNamed(self.getNibName(), owner: self, options: nil)
        self.addSubview(self.getHelperView())
        self.getHelperView().frame = self.bounds
    }
}

class HelpView: ReusableView {
    @IBOutlet var view: UIView!

    override func getHelperView() -> UIView! {
         return view;
    } 

    override func getNibName() -> String {
         return "NibName";
    } 
}

类的可重用代码

1 个答案: