我的型号代码:
public function get_news($id)
{
$this->db->select('*');
$this->db->limit(1);
$this->db->order_by("id", "desc");
$this->db->from('news_article');
$this->db->where('news_article.submenuid', $id);
$query = $this->db->get();
$result=$query->result();
if($result)
{
return $result;
}
else
{
return false;
}
}
我的控制器代码是:
public function get_single_news($id)
{
$data=array();
$data['single']=$this->Syllabus_model->get_news($id);
var_dump($data['single']);
$data['maincontent']=$this->load->view('single_news/get_single_news', $data, true);
$this->load->view('welcome_message',$data);
}
我的观看代码是:
<?php
if(!empty($single){
forech($single as $values){
?>
<?php $values->id;?>
<?php
}
}
else
{
echo "Have Not Data;
}
?>
数据由var_dump($ data ['single']);
进入控制器array(1){[0] =&gt; object(stdClass)#31(19){[“id”] =&gt; string(1)“3”[“Title_B”] =&gt; string(35)“ঈমাননওার”[“Title_E”] =&gt; string(35)“ঈমাননওার”[“Title_A”] =&gt; string(35)“ঈমাননওার”[“short_D_B”] =&gt; string(35)“ঈমাননওার”[“short_D_E”] =&gt; string(35)“ঈমাননওার”[“short_D_A”] =&gt; string(35)“ঈমাননওার”[“long_D_B”] =&gt; string(42)“
ঈমাননওার “[”long_D_E“] =&gt;字符串(42)”
ঈমাননওার “[”long_D_A“] =&gt;字符串(42)”
ঈমাননওার “[”imageurl“] =&gt; string(30)”./ upload / 965757556a5a33d79.jpg“[”slideimage“] =&gt; string(3)”YES“[”imagegallary“] =&gt; string(3)”是“[”titilerecent“] =&gt;字符串(3)”是“[”createdate“] =&gt;字符串(19)”2016-06-06 18:19:38“[”userid“] =&gt;字符串(1)“1”[“status”] =&gt; string(1)“0”[“menuid”] =&gt; string(1)“1”[“submenuid”] =&gt; string(3)“120 “}}
错误消息
致命错误:未捕获的TypeError:传递给CI_Exceptions :: show_exception()的参数1必须是Exception的实例,给出ParseError的实例,在C:\ xampp \ htdocs \ tale23 \ tale23 \ system \ core \ Common中调用。 php在第658行并在C:\ xampp \ htdocs \ tale23 \ tale23 \ system \ core \ Exceptions.php中定义:190堆栈跟踪:#0 C:\ xampp \ htdocs \ tale23 \ tale23 \ system \ core \ Common.php (658):CI_Exceptions-&gt; show_exception(Object(ParseError))#1 [内部函数]:_ exception_handler(Object(ParseError))#2 {main}抛出C:\ xampp \ htdocs \ tale23 \ tale23 \ system \ core第190行的Exceptions.php 遇到PHP错误
严重性:错误
消息:未捕获的TypeError:传递给CI_Exceptions :: show_exception()的参数1必须是Exception的实例,给出ParseError的实例,在C:\ xampp \ htdocs \ tale23 \ tale23 \ system \ core \ Common.php中调用在第658行并在C:\ xampp \ htdocs \ tale23 \ tale23 \ system \ core \ Exceptions.php中定义:190堆栈跟踪:#0 C:\ xampp \ htdocs \ tale23 \ tale23 \ system \ core \ Common.php( 658):CI_Exceptions-&gt; show_exception(Object(ParseError))#1 [内部函数]:_ exception_handler(Object(ParseError))#2 {main}抛出
文件名:core / Exceptions.php
行号:190
回溯:
请帮帮我
答案 0 :(得分:0)
尝试评论或删除var_dump
和$data['maincontent']
行,如下所示:
//var_dump($data['single']);
//$data['maincontent']=$this->load->view('single_news/get_single_news', $data, true);
我不认为加载视图并将其传递给视图是正确的。