我对folium很新,在尝试通过循环包含坐标对的pandas AttributeError
和folium
地图时,面对df
时遇到 location_name location
'foo' [40.736932, -73.997043]
'bar' [40.738859, -73.995058]
'xyz' [40.744085, -74.000394]
每对的名称,例如
center_map = [40.738859, -73.995058]
map_1 = folium.Map(location=center_map, tiles=None, zoom_start=12)
for i in df:
folium.Marker(i.location,
popup=i.location_name,
icon=folium.Icon(color='purple')
).add_to(map_1)
使用以下代码:
AttributeError: 'Series' object has no attribute 'get_name'
但是,我收到以下错误:
element.py
我认为是由generic.py
中的folium
和/Users/martin/anaconda/envs/py3k/lib/python3.5/site-packages/folium/element.py in add_children(self, child, name, index)
85 def add_children(self, child, name=None, index=None):
86 """Add a child."""
---> 87 return self.add_child(child, name=name, index=index)
88
89 def add_child(self, child, name=None, index=None):
/Users/martin/anaconda/envs/py3k/lib/python3.5/site-packages/folium/element.py in add_child(self, child, name, index)
90 """Add a child."""
91 if name is None:
---> 92 name = child.get_name()
93 if index is None:
94 self._children[name] = child
/Users/martin/anaconda/envs/py3k/lib/python3.5/site-packages/pandas/core/generic.py in __getattr__(self, name)
2667 if name in self._info_axis:
2668 return self[name]
-> 2669 return object.__getattribute__(self, name)
2670
2671 def __setattr__(self, name, value):
AttributeError: 'Series' object has no attribute 'get_name'
文件引起的:
{{1}}
感谢任何有关如何解决这个问题的帮助!
答案 0 :(得分:1)
迟到总比不到好!到达同一错误代码后到达这里,我忘了打电话给folium.Popup(details)我想这是需要的孩子。
此行引起的错误
popup=i.location_name
应该是
popup = folium.Popup(i.location_name)