我有一个表A,其中包含以下列:
AId - TargetId - IsActive
对应于此表,我有下面的类(带有额外的计算属性)和mapper:
public class A
{
public virtual long AId { get; set; }
public virtual int TargetId { get; set; }
public virtual int IsActive { get; set; }
//calculated property, doesn't exist in the table
public virtual bool IsClientSide
{
get { return ((this.TargetId & TargetEnum.ClientSide) != 0); }
}
}
using NHibernate.Mapping.ByCode;
using NHibernate.Mapping.ByCode.Conformist;
using NHibernate.Type;
using ANamespace.A;
namespace mapping
{
public class AMap : ClassMapping<A>
{
public AMap()
{
this.Cache(x => { x.Usage(CacheUsage.NonstrictReadWrite); x.Region("LongTerm"); x.Include(CacheInclude.All); });
this.Lazy(false);
this.Mutable(true);
this.DynamicUpdate(true);
this.Id(x => x.AId, map => map.Generator(Generators.Native));
this.Property(x => x.TargetId, map => { map.NotNullable(true); map.Type<EnumType<TargetEnum>>(); });
this.Property(x => x.IsActive, map => map.NotNullable(true));
}
}
}
我没有映射这个IsClientSide属性,因为它不在表中。但是我想在我的查询中使用它,如下所示:
A aobject = null;
alist = session.QueryOver(() => aobject)
.Where(a => a.IsClientSide)
.And(tt => a.IsActive)
......
我找到了Hendry Luk&#34; Linq-ing计算属性&#34;发布但ILinqToHqlGenerator似乎过于复杂,无法使用这个小小的属性。
如何在我的mapper类中制定 IsClientSide
属性呢?
答案 0 :(得分:4)
我们需要1) Formula
映射和2)bitwise
operator
Property(x => x.IsClientSide, map =>
{
map.Formula("(Target_ID & 1 <> 0)");
});
和属性应该由NHibernate分配
public virtual bool IsClientSide { get; protected set; }
现在我们可以在任何查询中使用IsClientSide
...