LEFT JOIN

Question

我一直在用这个工作几个小时，但现在是时候让第二双眼睛来看它......

我有这个mySQL查询：

 SELECT
     vaktliste.id AS id,
     brukere.navn AS bruker,
     steder.navn AS sted,
     vaktliste.start AS vl_start,
     vaktliste.slutt AS vl_slutt,
     timeliste.start AS tl_start  
 FROM brukere, steder, vaktliste  
 LEFT JOIN timeliste
 ON timeliste.sted=vaktliste.sted
 AND timeliste.bruker=vaktliste.bruker
 AND DATE(timeliste.start)=DATE(vaktliste.start)  
 WHERE brukere.id=vaktliste.bruker
 AND steder.id=vaktliste.sted
 AND timeliste.start IS NULL
 AND vaktliste.firma=15
 AND vaktliste.bruker = 381
 AND MONTH(vaktliste.start) = 6
 AND YEAR(vaktliste.start) = 2016  
 ORDER BY vaktliste.start ASC, brukere.navn

当浏览器“运行”时，它没有结果，但在phpMyAdmin中，它得到了一个结果。

当我删除ORDER BY时，我在浏览器中得到了一个结果...

任何人都可以告诉我为什么ORDER BY行会弄乱查询吗？

这是生成查询的PHP文件中的一些代码：

echo("<table id=\"ansatt_tabell\" class=\"ui unstackable celled table\">
                <thead>
                    <tr>
                        <th>Ansatt</th>
                        <th>Kunde</th>
                        <th>Dato</th>
                        <th>Start</th>
                        <th>Slutt</th>
                        <th></th>
                    </tr>
                </thead>
                <tbody>");



        //Til sammenlangt
        $timer_totalt = 0;
        $kilometer_totalt = 0;

        //Kobler til mySQL-databasen
        include("../koble_til_db.php");


        //Kjører spørring
        $query = "SELECT vaktliste.id AS id, brukere.navn AS bruker, steder.navn AS sted, vaktliste.start AS vl_start, vaktliste.slutt AS vl_slutt, timeliste.start AS tl_start FROM brukere, steder, vaktliste LEFT JOIN timeliste ON timeliste.sted=vaktliste.sted AND timeliste.bruker=vaktliste.bruker AND DATE(timeliste.start)=DATE(vaktliste.start) WHERE brukere.id=vaktliste.bruker AND steder.id=vaktliste.sted AND timeliste.start IS NULL AND vaktliste.firma=$firma";

        //Sorterer i henhold til bokser over
        if($timeliste_ansatt != 0){
            $query = $query . " AND vaktliste.bruker = $timeliste_ansatt";
        }

        if($timeliste_sted != 0){
            $query = $query . " AND vaktliste.sted = $timeliste_sted";
        }

        if($timeliste_maaned != 0){
            $query = $query . " AND MONTH(vaktliste.start) = $timeliste_maaned";
        }

        if($timeliste_aar != 0){
            $query = $query . " AND YEAR(vaktliste.start) = $timeliste_aar";
        }

        $query = $query . " ORDER BY vaktliste.start ASC, brukere.navn ASC";


        $result = mysqli_query($connect, $query);

        while($newArray = mysqli_fetch_array($result)){

            $id = $newArray['id'];
            $bruker = $newArray['bruker'];
            $sted = $newArray['sted'];
            $start = $newArray['vl_start'];
            $start_dato = date('d.m.y', strtotime($start));
            $start_tid = date('H:i', strtotime($start));
            $slutt = $newArray['vl_slutt'];
            $slutt_tid = date('H:i', strtotime($slutt));


            //Innhold tabell
            echo("<tr>
                    <td>$bruker</td>
                    <td>$sted</td>
                    <td class=\"center aligned\">$start_dato</td>
                    <td class=\"center aligned\">$start_tid</td>
                    <td class=\"center aligned\">$slutt_tid</td>
                    <td class=\"collapsing center aligned\"><div class=\"mini ui green basic button\" onClick=\"adm_timeliste_overfor(this, $id)\">Registrer timer</div></td>
                </tr>");


        }//while

        //Avslutter tabell
        echo("</tbody>

收到的错误讯息是：

  

SELECT将检查超过MAX_JOIN_SIZE行;检查你的WHERE并使用SET SQL_BIG_SELECTS = 1或SET MAX_JOIN_SIZE =＃如果SELECT没问题