如何删除非倒转的非ASCII字符''''''' ," L"等,在xml c#
中我尝试过像Sanitize Xml String
(character >= 0x20 && character <= 0xD7FF) ||
(character >= 0xE000 && character <= 0xFFFD) ||
(character >= 0x10000 && character <= 0x10FFFF)
使用Regex如下:
Regex.Replace(inputText, @"[^><#\w\.@-]", "");
(or)
string str = str.replace(/[^A-Za-z 0-9 \.,\?""!@#\$%\^&\*\(\)-_=\+;:<>\/\\\|\}\{\[\]`~]*/g, '')
和Pattern替换如下:
string pattern = @"#x((10?|[2-F])FFF[EF]|FDD[0-9A-F]|7F|8[0-46-9A-F]9[0-9A-F])";
最后用
XmlConvert.VerifyXmlChars(text);
但没有用,字符如下所示: &#39;┌&#39;&#39;├&#39;&#39;⌐&#39;&#39;┐&#39;&#39;┴&#39;
请看这个链接 https://en.wikipedia.org/wiki/Western_Latin_character_sets_%28computing%29
└U+ 2514 C0 C0
┘U + 2518 D9 D9
请帮帮我。提前致谢
答案 0 :(得分:1)
Try This
string s = "søme string";
s = Regex.Replace(s, @"[^\u0000-\u007F]", string.Empty);