我想在我的编码中实现这个方法,但我不知道怎么做,有人可以给我一些关于如何做的建议吗?
下面是我想要使用的编码截图。
这是我的编码。 ViewOrder.javapublic class ViewOrder extends AppCompatActivity implements ListView.OnItemClickListener {
public static final String JSON_URL = "http://dashberry.com/strack/mobile/viewOrder.php";
private ListView listView;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_view_order);
listView = (ListView) findViewById(R.id.listView);
sendRequest();
}
private void sendRequest(){
StringRequest stringRequest = new StringRequest(JSON_URL, new Response.Listener<String>() {
public void onResponse(String response) {
showJSON(response);
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(ViewOrder.this,error.getMessage(),Toast.LENGTH_LONG).show();
}
});
RequestQueue requestQueue = Volley.newRequestQueue(this);
requestQueue.add(stringRequest);
}
private void showJSON(String json){
ParseJSON pj = new ParseJSON(json);
pj.parseJSON();
CustomList cl = new CustomList(this, ParseJSON.itemName,ParseJSON.origin,ParseJSON.destination);
listView.setAdapter(cl);
}
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
Intent intent = new Intent(this, ItemDetail.class);
//ParseJSON<String> map = (ParseJSON)parent.getItemAtPosition(position);
//HashMap<String,String> map = (HashMap)parent.getItemAtPosition(position);
// String empId = map.get(ParseJSON.itemName).toString();
// intent.putExtra("item_id", empId);
startActivity(intent);
}
}
ParseJSON.java
public class ParseJSON {
public static String[] itemName;
public static String[] origin;
public static String[] destination;
public static final String JSON_ARRAY = "result";
public static final String KEY_NAME = "itemName";
public static final String KEY_ORIGIN = "origin";
public static final String KEY_DESTINATION = "destination";
private JSONArray users = null;
private String json;
public ParseJSON(String json){
this.json = json;
}
protected void parseJSON(){
JSONObject jsonObject=null;
try {
jsonObject = new JSONObject(json);
users = jsonObject.getJSONArray(JSON_ARRAY);
itemName = new String[users.length()];
origin = new String[users.length()];
destination = new String[users.length()];
for(int i=0;i<users.length();i++){
JSONObject jo = users.getJSONObject(i);
itemName[i] = jo.getString(KEY_NAME);
origin[i] = jo.getString(KEY_ORIGIN);
destination[i] = jo.getString(KEY_DESTINATION);
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}
基本上我想要的是当用户单击列表中的项目时,它将使用户使用某些数据(itemName)进行下一个活动。
答案 0 :(得分:0)
实现onItemClick like
@Override
public void onItemClick(AdapterView<?> l, View v, int position, long id) {
//start a new Activity via Intent
Intent intent = new Intent();
intent.setClass(this, ItemDetail.class);
//you can putExtra only position or id
intent.putExtra("position", position);
intent.putExtra("id", id);
startActivity(intent);
}
您应该创建名为ItemDetail的Anther Activity,您可以通过在onCreate()
中添加此代码来获取ID和位置,以了解被点击的项目
Intent intent = getIntent();
String position = intent.getStringExtra("position");
String id = intent.getStringExtra("id");