Question

我想找到所有年份值以20开头的对象...所以我想搜索20 *，其中*是外卡。我尝试了类似

的东西

'match_phrase_prefix': { 'year': { 'query': '20*', 'max_expansions': 50}}

但我想这只适用于字符串。我如何为整数做这个？

编辑：我找到了一个解决方案......它不漂亮但是有效

year_query = '20'
if len(str(year_query)) < 4:
    try:
        low_year, high_year = extend_year(int(year_query))
        filter_list.append({"range": {"year": {"gte": low_year, "lte": high_year}}})
    except ValueError:
        print "Not a valid input for year"
        pass
else:
    for year in year_query.split(','):
        if '-' in year:
            year_range = year.split('-')
            high_year = year_range[1].strip()
            if len(high_year) < 4:
                low_year, high_year = extend_year(high_year)
                try:
                    filter_list.append({"range" : {"year" : {"gte" : int(year_range[0].strip()),"lte" : int(high_year),"format": "yyyy"}}})
                except ValueError:
                    print "Not a valid input for year"
                    pass
            else:
                try:
                    filter_list.append({ "match": {"year": int(year.strip()) }})
                except ValueError:
                    print "Not a valid input for year"
                    pass

具有功能

def extend_year(input_year):
    length = len(str(input_year))
    if length == 4:
        return input_year, 0
    elif length == 3:
        return input_year*10, int(str(input_year) + '9')
    elif length == 2:
        return input_year*100, int(str(input_year) + '99')
    elif length == 1:
        return input_year*1000, int(str(input_year) + '999')
    elif length == 0:
        return 0, 9999
    else:
        return input_year, 0

如果有人能提出更好的解决方案，请告诉我

Answer 1

这应该有效

'range': { 'year': { 'gte': 2000, 'max_expansions': 50}}

elasticsearch：使用通配符表示整数值

1 个答案: