Question

我在不相关的文本中嵌入了列表，如下所示：

Unrelated TextUnrelated TextUnrelated Text

Study Durations(HH:MM) Time 
Total 04:00 
Upright 02:08 
Supine 01:49 
Other  03:10 
More Other 12:34

Unrelated TextUnrelated TextUnrelated TextUnrelated TextUnrelated TextUnrelated TextUnrelated TextUnrelated TextUnrelated TextUnrelated Text

Study Durations(HH:MM) Time 
Total 24:00 
Upright 12:18 
Supine 11:42 
PostPr  n/a

我想抓住这些小组来获取这个：

示例1输出

Study Durations(HH:MM) Time 
Total 04:00 
Upright 02:08 
Supine 01:49 
Other  03:10 
More Other 12:34

示例2输出

Study Durations(HH:MM) Time 
Total 24:00 
Upright 12:18 
Supine 11:42 
PostPr  n/a

我试过以下正则表达式

Pattern Total_pattern = Pattern.compile("Study Durations\\(HH:MM\\) Time\\s*(?:\\n[A-Za-z]+\\s+(?:\\d+(?::\\d+)?|n/a))",Pattern.DOTALL);

但我只能

Study Durations(HH:MM) Time 
Total 04:00 


Study Durations(HH:MM) Time 
Total 24:00

Answer 1

你可以使用这个正则表达式进行前瞻：

Study Durations\(HH:MM\) Time.*?(?=\n\n|\z)

请务必使用DOTALL修饰符以匹配各行。

Java模式：

Pattern Total_pattern = Pattern.compile(
     "Study Durations\\(HH:MM\\) Time.*?(?=\\n\\n|\\z)", Pattern.DOTALL);

RegEx Demo

如何使用正则表达式捕获可变长度列表

1 个答案: