Question

我有以下代码，这是我编写的模拟程序的精简版本：

import sched, time
import _thread as thread, threading

lock = threading.Lock()

f0=open("f0.out",'w',1)
f1=open("f1.out",'w',1)
f2=open("f2.out",'w',1)
# f3=open("f3.out",'w',1)
# f4=open("f4.out",'w',1)

# files = [f1,f2,f3,f4]
files = [f1,f2,]
def demoWrite(destFile):
    destFile.write("Hello\n")


def createSchedule(outFile):
    s = sched.scheduler(time.time, time.sleep)

    for i in range(1,100):
        s.enter(1,1,demoWrite,(outFile,))

    s.run()
    with lock:
        print('Thread Done',outFile)


createSchedule(f0)
f0.close()


for f in files:
    thread.start_new_thread ( createSchedule, (f,) )

for f in files:
    print(f)
    f.close()

print('Done')

我遇到的问题是它会创建文件，但不会写入文件，也不会打印Thread Done输出。

对于f0，但是没有线程，它可以毫无障碍地工作。

我在完整的程序中得到了同样的行为。

Answer 1

工作代码：

import sched, time
import threading

lock = threading.Lock()

f0=open("f0.out",'w',1)
f1=open("f1.out",'w',1)
f2=open("f2.out",'w',1)
# f3=open("f3.out",'w',1)
# f4=open("f4.out",'w',1)

# files = [f1,f2,f3,f4]
files = [f1,f2,]
def demoWrite(destFile):
    destFile.write("Hello\n")


def createSchedule(outFile):
    s = sched.scheduler(time.time, time.sleep)

    for i in range(1,100):
        s.enter(1,1,demoWrite,(outFile,))

    s.run()
    with lock:
        print('Thread Done',outFile)
        outFile.close()


createSchedule(f0)
f0.close()


for f in files:
    t = threading.Thread(target=createSchedule, args=(f,))
    t.start()
    # thread.start_new_thread (  )


print('Done')

我做了什么：

导入线程而不是_thread
将线程创建更改为t = threading.Thread(target=createSchedule, args=(f,)); t.start()

谢谢Tadhg McDonald-Jensen的评论，这使我指出了正确的方向

python多线程写入文件没有结果

1 个答案: