Question

我（从论坛上）获得了一个图像上传脚本，一旦它们具有相同的名称，就会用新的图像替换现有的图像。它适用于我的需要，但我需要图像在我的上传文件夹中。我该怎么做？

<?php
/*************************************************
 * Max's File Uploader
 *
 * Version: 1.0
 * Date: 2007-11-26
 *
 ****************************************************/
class maxUpload{
    var $uploadLocation;

    /**
     * Constructor to initialize class varaibles
     * The uploadLocation will be set to the actual 
     * working directory
     *
     * @return maxUpload
     */
    function maxUpload(){
        $this->uploadLocation = getcwd().DIRECTORY_SEPARATOR;
    }

    /**
     * This function sets the directory where to upload the file
     * In case of Windows server use the form: c:\\temp\\
     * In case of Unix server use the form: /tmp/
     *
     * @param String Directory where to store the files
     */
    function setUploadLocation($dir){
        $this->uploadLocation = $dir;
    }

    function showUploadForm($msg='',$error=''){
?>
       <div id="container">
            <div id="header"><div id="header_left"></div>
            <div id="header_main">Max's File Uploader</div><div id="header_right"></div></div>
            <div id="content">
<?php
if ($msg != ''){
    echo '<p class="msg">'.$msg.'</p>';
} else if ($error != ''){
    echo '<p class="emsg">'.$error.'</p>';

}
?>
                <form action="" method="post" enctype="multipart/form-data" >
                     <center>
                         <label>File:
                             <input name="myfile" type="file" size="30" />
                         </label>
                         <label>
                             <input type="submit" name="submitBtn" class="sbtn" value="Upload" />
                         </label>
                     </center>
                 </form>
             </div>
             <div id="footer"><a href="http://www.phpf1.com" target="_blank">Powered by PHP F1</a></div>
         </div>
<?php
    }

    function uploadFile(){
        if (!isset($_POST['submitBtn'])){
            $this->showUploadForm();
        } else {
            $msg = '';
            $error = '';

            //Check destination directory
            if (!file_exists($this->uploadLocation)){
                $error = "The target directory doesn't exists!";
            } else if (!is_writeable($this->uploadLocation)) {
                $error = "The target directory is not writeable!";
            } else {
                $target_path = $this->uploadLocation . basename( $_FILES['myfile']['name']);

                if(@move_uploaded_file($_FILES['myfile']['tmp_name'], $target_path)) {
                    $msg = basename( $_FILES['myfile']['name']).
                    " was uploaded successfully!";
                } else{
                    $error = "The upload process failed!";
                }
            }

            $this->showUploadForm($msg,$error);
        }

    }

}
?>

html代码如下：

<?php require_once("maxUpload.class.php"); ?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
   <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
   <title>File Uploader</title>
   <link href="style/style.css" rel="stylesheet" type="text/css" />
</head>

<body>
<?php
    $myUpload = new maxUpload(); 
    //$myUpload->setUploadLocation(getcwd().DIRECTORY_SEPARATOR);
    $myUpload->uploadFile();
?>
</body>

Answer 1

好吧，我能够通过修改$this->uploadLocation = getcwd().DIRECTORY_SEPARATOR;中的这一行来解决我的问题

$this->uploadLocation = getcwd().DIRECTORY_SEPARATOR."images". DIRECTORY_SEPARATOR;

谢谢大家。

如何将上传位置从工作目录更改为上载文件夹

1 个答案: