Question

我使用以下代码首先检查是否存在＆＃39;（＆＃39;在字符串中。如果是这样，我想将字符串分成两个，如下面的例子

['(Class 6)', '(0-60, 4yo+)', '1m4f Standard']
['(Class 6)', '(0-60, 4yo+) (1m4f50y)', '1m4f Standard','(1m4f50y)']

但出于某种原因，如果我运行以下代码：

if details[1].count('(') == 2:
            details = details[1].rsplit('(', 1)

我得到了

['(Class 6)', ['(0-60, 4yo+)', '1m4f50y)'], '1m4f Standard']`

我希望

['(Class 6)', '(0-60, 4yo+)', '1m4f Standard','(1m4f50y)']

Answer 1

rsplit()会返回一个列表，您将其放入details。如果您获取该列表的第一个元素[0]并将其放入您从details[1]获取数据的元素中，那么您应该得到您期望的结果。

if details[1].count('(') == 2:
    splitdata = details[1].rsplit('(', 1)
    details[1] = splitdata[0]
    details.extend(splitdata[1:])

Answer 2

这有点像你想要做的吗？

deets = [
    ['(Class 6)', '(0-60, 4yo+) (1m4f50y)', '1m4f Standard', '(1m4f50y)']
]

def separate_tuples(details: list) -> list:

    # Loop over each string in the list, but also get it's index
    for index, string in enumerate(details):

        # If the string has more than one tuple, remove it,
        if string.count('(') == 2:
            details.remove(string)

            # but keep using the removed string for the following:
            # separate it into parts
            for part in string.split(')', 1):
                # clear whitespace from either side
                part = part.strip()

                # if the part already exists in the list, get rid of the duplicate
                if part in details:
                    details.remove(part)

                # if the part doesn't end in a paren, add one and insert it at the current index
                # otherwise, just add the part with no extras
                details.insert(index, part + ')' if not part.endswith(')') else part)

            # Move the current item to the back of the list
            details.append(details.pop(index))

    return details


for deet in deets:
    print(separate_tuples(deet))

输出

['(Class 6)', '(0-60, 4yo+)', '1m4f Standard', '(1m4f50y)']

python：最后一次出现的拆分字符串似乎删除它而不是拆分它

2 个答案: