Question

我试图从今年（2016年）开始以相反的顺序印刷年份，例如：

为此我使用'for'循环：

$year1 = date("Y");
$endyear = date("Y")-10;
for ($year = $year1; $year < $endyear; $year--) {
    echo "The year is: $year <br>";
}

但它没有显示任何输出。即使我使用相同的代码来增加10年的年份，比如

$year1 = date("Y");
$endyear = date("Y")+10;
for ($year = $year1; $year < $endyear; $year++) {
    echo "The year is: $year <br>";
}

其输出是;

The year is: 2016
The year is: 2017
The year is: 2018
The year is: 2019
The year is: 2020
The year is: 2021
The year is: 2022
The year is: 2023
The year is: 2024
The year is: 2025

我的代码中出现了错误。请帮我按相反的顺序实现这一点。

Answer 1

for循环中的条件错误。根据你的问题，这是正确的代码：

<?php

$year1 = date("Y");
$endyear = date("Y")-10;
for ($year = $year1; $year >= $endyear; $year--) {
    echo "The year is: $year <br>";
}

?>

Answer 2

您需要做的就是翻转<

$year1 = date("Y");
$endyear = date("Y")-10;
for ($year = $year1; $year > $endyear; $year--) {
    echo "The year is: $year <br>";
}

Answer 3

不是$year < $endyear
但是：$ year＆gt; $ endyear

这样：

$year1 = date("Y");
$endyear = date("Y")-10;
for ($year = $year1; $year > $endyear; $year--) {
    echo "The year is: $year <br>";
}

Answer 4

试试这个： -

$years = range(date("Y")+9,date("Y")); // range(2025,2016)
foreach($years as $year){
  echo "The year is: $year <br>";
}

从今年开始以相反的顺序打印年份到PHP的最后10年

4 个答案: