Question

首先，我在列表中存储多个值。我想从消息框中获取列表输出中的所有元素，但它不起作用！我也尝试了许多方式，使得foreach循环在消息框下但不起作用。请帮帮我。The code is for message box. First is my code output and second is target output

Answer 1

此代码可以帮助您执行此操作：

让@RequestMapping(method = RequestMethod.POST) public String weatherPost(@ModelAttribute City city, ModelMap model) throws URISyntaxException{ String apiKey="myApIKey";//Removed my original API Key for posting. RestTemplate template = new RestTemplate(); String strUri= "http://api.openweathermap.org/data/2.5/weather?q="+city.getName()+",AU&appid="+apiKey+"&units=metric"; URI uri = new URI(strUri); RequestEntity<String> request = new RequestEntity<String>(HttpMethod.GET,uri); ResponseEntity <WeatherResponse> weatherResponse = template.exchange(uri, HttpMethod.GET, request, WeatherResponse.class); City myCity = new City(); model.put("weatherResponse", weatherResponse); model.put("city", myCity); return "weather"; }成为您已经拥有的字符串列表，您可以使用String.Join()方法来加入用分隔符分隔的字符串（这里我选择MyListValues作为分隔符）。现在看一下这个片段：

对于您的特定示例，最佳选项是在Student类中覆盖.ToString()方法。

对于使用类定义可能如下所示：

List<string>MyListValues= new List<string>(){"value 1","value 2","value 3","value 4","value 10","value 11"};
string delimiter=",";
string messageBoxContent=String.Join(delimiter,MyListValues);
MessageBox.Show(messageBoxContent);

你的列表迭代将是：

public class Student
{
    public int Id { get; set; }
    public string Name { get; set; }
    public string email { get; set; }
    // rest of properties and declarations
    //Class methods and constructors
    public override string ToString()
    {
        StringBuilder ObjectString = new StringBuilder();
        ObjectString.AppendLine("Stdent Details");
        ObjectString.AppendLine("Name :" + this.Name);
        ObjectString.AppendLine("ID :" + this.Id);
        ObjectString.AppendLine("Email :" + this.email);
        return ObjectString.ToString();
    }
}

或者

foreach (Student student in StudentList)
{
    MessageBox.Show(student.ToString());// Shows the message in each iteration
}

Answer 2

将str圈内的foreach变量更改为：

str += students.studentRegNo+ " " + students.studentName + " " + students.studentEmail+ Environment.NewLine;

如何在MessageBox中放置List的多个值

2 个答案: