Question

很抱歉标题混乱，不知道怎么说这个。

我有一个事件表，以及这些事件的赌注表。我已经获取了每个赛事的总金额，但我也想获取赔率（也就是说，一支球队的总数除以另一支球队的总数）。下注的参与者存储在horse表的data_bets列中。

例如，我想添加类似的内容：

SELECT 
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.challenger
    /
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.contestant
AS bet_odds

到我现有的查询：

SELECT *,
   SUM(data_bets.amount) AS total_pot,
   COUNT(data_bets.member) AS total_bets,
   COUNT(data_votes.member) AS total_votes,
   data_platforms.name AS platform_name, data_platforms.icon AS platform_icon
FROM data_events
   LEFT JOIN data_bets ON data_bets.event=data_events.id
   LEFT JOIN data_votes ON data_votes.content_type=2 AND data_votes.content_id=data_events.id
   LEFT JOIN data_platforms ON data_platforms.id=data_events.platform
WHERE status=1
GROUP BY data_events.id
ORDER BY total_pot DESC

这可以用一个查询吗？如果可能，我更愿意同时取challenger_odds和contestant_odds：

SELECT 
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.challenger
    /
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.contestant
AS challenger_odds, 
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.contestant
    /
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.challenger
AS contestant_odds

Answer 1

使用条件聚合：

SELECT (SUM(CASE WHEN data_bets.horse = data_events.challenger THEN data_bets.amount ELSE 0 END)  /
        SUM(CASE WHEN data_bets.horse = data_events.contestant THEN data_bets.amount END) 
       ) as bet_odds

检索两个SUM（col）JOIN的商在不同的值上

1 个答案: