Question

我刚刚开始学习python，并且在尝试编写简单的1-D版单人战舰时遇到了一些麻烦。

我似乎无法做出两件事：

我创建了一个一维列表（这是游戏玩法板），但需要显示/打印列表中重复元素的索引。换句话说，我如何打印一个仅显示我板上元素索引的列表？
我想用＆＃34; *＆＃34;替换该元素如果这是一个错误的猜测。例如，如果我错误地将位置猜测为5个元素的板中的4，我想显示：

1 2 3 * 5

此外，我想将获胜的热门歌曲显示为＆＃34; X＆＃34;：

1 2 X * 5

这是我目前的代码：

from random import randint

ship=randint(0, 5)
board = ["O","O","O","O","O"]

print ("Let's play Battleship!")

attempts = 1
while attempts < 4:
    print (board)
    guess = int(input("Guess Where My Ship Is: "))
    if guess == ship:
        print ("Congratulations Captain, you sunk my battleship!")
        break
    else:
        print ("You missed my battleship!")
        if attempts<3:
            print("Try again!")
        elif attempts==3:
            print("Better luck next time, Captain!")

    attempts+=1

感谢并为这个蹩脚的问题道歉。

Answer 1

良好做法：将电路板尺寸设置为变量，以便您可以定期参考。把它放在顶部

size = 5 # Can be changed later if you want to make the board bigger

接下来，根据

选择您的发货地点

ship = randint(0, size)

不要将电路板填充为0，而是动态生成电路板，以便它已经预先填充了可能的值。

board = [] # Creating an empty board
for i in range(1, size):
  position = str(i) # Converting integers to strings
  board.append(position) # Adding those items to the board

然后，在游戏逻辑内部，＆＃34;你错过了我的战舰＆＃34;线，改变板上的相关方块

...
print("You missed my battleship!")
number_guess = int(guess) - 1 # Because lists are zero-indexed
board[number_guess] = "*" # Assign "*" to the spot that was guessed
if attempts < 3:
    ...

Answer 2

为了实现您的两种显示功能，我建议您只让board列表保留显示值，因为您还没有在其他任何地方使用它。

from random import randint

ship=randint(1, 5)
board = ['1', '2', '3', '4', '5']

print ("Let's play Battleship!")

attempts = 1
while attempts < 4:
    print(' '.join(board))
    guess = int(input("Guess Where My Ship Is: "))
    if guess == ship:
        print ("Congratulations Captain, you sunk my battleship!")
        board[guess - 1] = 'X'
        break
    else:
        print ("You missed my battleship!")
        board[guess - 1] = '*'
        if attempts<3:
            print("Try again!")
        elif attempts==3:
            print("Better luck next time, Captain!")
    attempts+=1

print(' '.join(board))

还有一件事：当您选择船舶的索引（应该在范围[1,5]中）时，您有一个错误，我也已经纠正过了。

如果你正在扩展你的战舰计划，你必须有一个打印出列表索引的功能（除非值是'*'或'X'），一种方法是简单地做：

def display(b):
    print(' '.join(y if y in 'X*' else str(x + 1) for x, y in enumerate(b)))

列出一维Python战舰的问题

2 个答案: