我对Android Studio相当陌生,我正在使用下面的代码尝试制作它,以便不是总是提示用户登录,而是应该保存/注册用户首先去,所以他们总是在应用程序运行时登录,即跳过登录。
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
// declaring variebles
etUsername = (EditText)findViewById(R.id.etUsername);
etPassword= (EditText)findViewById(R.id.etPassword);
btnLogin = (Button)findViewById(R.id.btnLogin);
etIpAddress = (EditText) findViewById(R.id.etIpAddress);
// setting up things for login button
btnLogin.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String ipAddress = etIpAddress.getText().toString();
SharedPreferences sharedPreferences = PreferenceManager.getDefaultSharedPreferences(LoginActivity.this);
sharedPreferences.edit()
.putString("ip", ipAddress)
.apply();
String username = etUsername.getText().toString().trim();
String password = etPassword.getText().toString().trim();
performLogin(username, password, ipAddress);
}
});
}
答案 0 :(得分:0)
只需检查onCreate
是否存在以前的ip
值
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
SharedPreferences sharedPreferences = PreferenceManager.getDefaultSharedPreferences(LoginActivity.this);
if (sharedPreferences.contains("ip")) {
performLogin(username, password, sharedPreferences.getString("ip","default value here"));
}
//other code
}