Question

我在linux上运行xampp。的index.php

    <form class="well" action="upload.php" method="post" enctype="multipart/form-data">
        <div class="form-group">
            <label for="file">Select a file to upload</label>
            <input type="file" name="file">
            <p class="help-block">Only jpg, jpeg, png, wav, mp3, wav and mp4 files are allowed.</p>
        </div>
        <input type="submit" class="btn btn-lg btn-primary" value="Upload">
    </form>

upload.php的

<?php
    if ($_SERVER['REQUEST_METHOD'] == 'POST') {

        $name     = $_FILES['file']['name'];
        $tmpName  = $_FILES['file']['tmp_name'];
        $error    = $_FILES['file']['error'];
        $size     = $_FILES['file']['size'];
        $ext      = strtolower(pathinfo($name, PATHINFO_EXTENSION));

        switch ($error) {
            case UPLOAD_ERR_OK:
                $valid = true;
                //validate file extensions
                if ( !in_array($ext, array('jpg','jpeg','png','mp3', 'mp4', 'wav', 'webm')) ) {
                    $valid = false;
                    $response = 'Invalid file extension.';
                }
                //validate file size
                /*if ( $size/1024/1024 > 2 ) {
                    $valid = false;
                    $response = 'File size is exceeding maximum allowed size.';
                }*/
                //upload file
                if ($valid) {
                    $targetPath =  'uploads/';

                    move_uploaded_file($tmpName,$targetPath);
                    header( 'Location: index.php' ) ;
                    exit;
                }
                break;
            case UPLOAD_ERR_INI_SIZE:
                $response = 'The uploaded file exceeds the upload_max_filesize directive in php.ini.';
                break;
            case UPLOAD_ERR_FORM_SIZE:
                $response = 'The uploaded file exceeds the MAX_FILE_SIZE directive that was specified in the HTML form.';
                break;
            case UPLOAD_ERR_PARTIAL:
                $response = 'The uploaded file was only partially uploaded.';
                break;
            case UPLOAD_ERR_NO_FILE:
                $response = 'No file was uploaded.';
                break;
            case UPLOAD_ERR_NO_TMP_DIR:
                $response = 'Missing a temporary folder. Introduced in PHP 4.3.10 and PHP 5.0.3.';
                break;
            case UPLOAD_ERR_CANT_WRITE:
                $response = 'Failed to write file to disk. Introduced in PHP 5.1.0.';
                break;
            case UPLOAD_ERR_EXTENSION:
                $response = 'File upload stopped by extension. Introduced in PHP 5.2.0.';
                break;
            default:
                $response = 'Unknown error';
            break;
        }

        echo $response;
    }

    ?>

Phpinfo：文件上传，最大文件大小128M。 uploads文件夹为空，它位于脚本所在的根目录中，没有显示错误，脚本似乎没有错误

Answer 1

您应该检查move_uploaded_file的返回值。

if ($valid) 
{
    $targetPath =  'uploads/';

    if(move_uploaded_file($tmpName,$targetPath))
    {
       header( 'Location: index.php' ) ;
       exit;
    }
    else
    {
        $response = 'Moving the file to the target directory failed.';
    }
}

如果这会给您一个错误，请使用$targetPath的绝对路径。

编辑：您还需要包含要用作目标的文件名，而不仅仅是目录。所以将代码更改为：

    if(move_uploaded_file($tmpName, $targetPath . $name))
    {

Answer 2

所以你需要到达你想要访问的文件夹。我有一段时间没想到同样的问题。我找到的解决方案是使用$ targetpath执行此操作：

您需要获取网络服务器路径，为此，您需要使用dirname(__FILE__)功能。取决于您将在文件路径中走多远。例如，我需要访问文件夹“nydemo1 / bilder / images / folders /”然后我需要这个文件路径变量：

dirname(dirname(dirname(__FILE__)) //因为这是3个文件夹

希望这有帮助

文件未上传

2 个答案: