所以我有一个具有Point
类的合成程序,并且在Line
类中使用Point类isValid
方法,以确保用户在继续之前输入正确的值。
基本上,当他们输入我的主要课程enterLine()
中的值时,他们必须继续输入,直到它满足Point中的isValid()
和Line中validateLine()
的规则。
// This method is in the Point class and will be used by validateLine()
public static boolean isValid(int x, int y)
{
Dimension screenSize = Toolkit.getDefaultToolkit().getScreenSize();
int maxHeight = screenSize.height;
int maxWidth = screenSize.width;
if (x < 0 || y < 0 || x > maxWidth || y > maxHeight)
{
return false;
}
return true;
}
// This method is in the Line class, uses isValid() from Point Class
public static boolean validateLine(int x1, int y1, int x2, int y2, int width)
{
if (Point.isValid(x1, y1) && Point.isValid(x2, y2))
{
return true;
}
return false;
}
// This method is in main, it prompts user to enter two valid Points.
public static Line enterLine(int line, Scanner kb)
{
System.out.println("Please enter two x's and y's values, a width, and color");
int x1 = kb.nextInt();
int x2 = kb.nextInt();
int y1 = kb.nextInt();
int y2 = kb.nextInt();
int newWidth = kb.nextInt();
String color = kb.next();
return new Line(x1, x2, y1, y2, color, newWidth);
}
答案 0 :(得分:0)
假设您正在询问如何反复提示用户输入x
和y
值,如果它无效,那么您将使用do while
或{{1循环。
你会做类似的事情:
while