Question

我一直在搜索此错误并阅读各种stackoverflow，Apple文档和博客答案，但我仍然遇到问题。我有一个符合NSData和NSCoding的类，它将存储6个属性中的3个。当在所需的方便init中调用self.init时，我在调用中得到一个错误“额外参数'groomedStatus'，”即使self.init签名与init完全匹配（我复制并粘贴）。这是相关的代码：

class Trail: NSObject, NSCoding {
var name: String
var difficulty: Difficulty
var haveSkied: Bool
var season: Season = .winter
var open: String?
var groomedStatus: String?

init(name: String, difficulty: Difficulty, haveSkied: Bool, season: Season, open: String?, groomedStatus: String?) {
    self.name = name
    self.difficulty = difficulty
    self.haveSkied = haveSkied
    self.season = season
    self.open = open
    self.groomedStatus = groomedStatus
}

required convenience init(coder aDecoder: NSCoder) {

    let haveSkied = aDecoder.decodeObjectForKey("haveSkied") as! Bool
    let open = aDecoder.decodeObjectForKey("open") as? String
    let groomedStatus = aDecoder.decodeObjectForKey("groomedStatus") as? String


    self.init(name: String, difficulty: Difficulty, haveSkied: Bool, season: Season, open: String?, groomedStatus: String?) {
        self.name = name
        self.difficulty = difficulty
        self.haveSkied = haveSkied
        self.season = season
        self.open = open
        self.groomedStatus = groomedStatus
    }

func encodeWithCoder(aCoder: NSCoder) {
    aCoder.encodeBool(haveSkied, forKey: "haveSkied")
    aCoder.encodeObject(open, forKey: "open")
    aCoder.encodeObject(groomedStatus, forKey: "groomedStatus")
}

}

Answer 1

问题源于您致电self.init()的方式。您在代码中执行此操作的方式本质上是尝试重新定义它，这对编译器没有意义。这就是你应该在便利初始化程序中调用self.init()的方法。

self.init(name: "yourActualNameString", difficulty: Difficulty(), haveSkied: true, season: .winter, open: "yourActualOpenString", groomedStatus: "yourActualGroomedStatusString")

在self.init Swift 2.2中调用额外的参数

1 个答案: