此处有 temp.file
文件var c = new Company(null, null);
c.Enumerator = new ReverseEnumeration(c);
我正在使用Line no1
Line no2
Line no3
Line no4
Line no5
abc
这打印了我的线" abc"。
但是我想要打印它上面的4行......
因此,所需的输出应为
less temp.file|grep -i "abc"
怎么样,我能得到它。
答案 0 :(得分:2)
GNU grep中有一个选项:-B
less temp.file | grep -B4 -i "abc"
来自上下文线控制的手册页:
-A NUM, --after-context=NUM
Print NUM lines of trailing context after matching lines. Places a line containing a group separator (--) between
contiguous groups of matches. With the -o or --only-matching option, this has no effect and a warning is given.
-B NUM, --before-context=NUM
Print NUM lines of leading context before matching lines. Places a line containing a group separator (--) between
contiguous groups of matches. With the -o or --only-matching option, this has no effect and a warning is given.
-C NUM, -NUM, --context=NUM
Print NUM lines of output context. Places a line containing a group separator (--) between contiguous groups of
matches. With the -o or --only-matching option, this has no effect and a warning is given.