Question

这是我的代码：

name = input("What is your name? ")
print name + " do you want to play a game?"
answer = input("To play the game, type either yes or no. ")
if answer == yes:
    print "Great," + name + "lets get started!"
elif answer == no:
    print "Okay, good bye!"

import random

number = random.randint(1,50)
guess = input ("Pick a number between 1 and 50. This number cannot be a decimal. ")
if guess > number:
    print "Your guess is too high!"
elif guess < number:
    print "Your guess is too low!"
while guess != number:
    print "Try again!"
else import random
    number = random.randint(1,50)
if guess == number:
    print "You guessed it!"
    print "Great job."
print "Do you want to play again?"

while answer == yes:
    import random

    number = random.randint(1,50)
    guess = input ("Pick a number between 1 and 50. This number cannot be a decimal. ")
    if guess > number:
        print "Your guess is too high!"
    elif guess < number:
        print "Your guess is too low!"
    while guess != number:
        print "Try again!"
    if guess == number:
        print "You guessed it!"
        print "Great job."
    print "Do you want to play again?
elif answer == no:
    print "Okay. Good game " + name + "!"
    print "Play again soon!"

好的，我的第一个问题是为什么python不能将name变量的输入识别为字符串。

第二个问题是最后一个elif语句一直给我一个语法错误。我不知道为什么。

最后一个问题是，我可以更轻松地循环此代码吗？

Answer 1

在Python 2x版本中，input()将变量变为integer，您可以使用raw_input()将其作为字符串。

因此，基本上将input()更改为raw_input()，以便将数据作为字符串。

在Python 3x版本中没有raw_input，只有input（），它将数据作为字符串。

第二个问题;

elif guess < number:

    print "Your guess is too low!"

while guess != number:

    print "Try again!"

else import random

    number = random.randint(1,50)

这不是正确的语法，您的else需要一个if块。如果没有else阻止，您就无法使用if。如果您想一秒钟，这是有道理的。

您的上一个问题不符合SO规则。

Noob程序员无法找出简单的问题

1 个答案: