Question

我使用以下内容显示一些送货方式：

foreach ($this->shipments_shipment_rates as $shipment_shipment_rates){
    if(is_array($shipment_shipment_rates)) {
        foreach ($shipment_shipment_rates as $shipment_shipment_rate) {
echo str_replace('name="virtuemart_shipmentmethod_id"', 'name="virtuemart_shipmentmethod_id" onclick="return ProOPC.setshipment(this);"', $shipment_shipment_rate);
            echo '<div class="clear"></div>';
        }

现在，如果在第一个回声之前我做了这样的if条件：

$myvariable = echo str_replace('name="virtuemart_shipmentmethod_id"', 'name="virtuemart_shipmentmethod_id" onclick="return ProOPC.setshipment(this);"', $shipment_shipment_rate);
if (strpos ($myvariable, 3) !== false) {
    echo "I found my shipping method"
}

然后就像strpos总是如此。即使在$ myvariable里面也没有价值3.任何想法？

我也可以通过这样做来隐藏运输方法：

If(my_condition_with_strpos) {
    echo '<div style="display:none;">' . str_replace('name="virtuemart_shipmentmethod_id"', 'name="virtuemart_shipmentmethod_id" onclick="return ProOPC.setshipment(this);"', $shipment_shipment_rate) . '</div>'
}

提前谢谢

Answer 1

您将值3搜索为整数，请参阅此示例：

<?php
$string = 'asdsad';
$myvariable = str_replace('name="virtuemart_shipmentmethod_id"', 'name="virtuemart_shipmentmethod_id" onclick="return ProOPC.setshipment(this);"', $string);

if (strpos($myvariable, '3') !== false) {
    echo "I found my shipping method 1";
}
else {
    echo "Not found 1";
}

$string = '3';
$myvariable = str_replace('name="virtuemart_shipmentmethod_id"', 'name="virtuemart_shipmentmethod_id" onclick="return ProOPC.setshipment(this);"', $string);

if (strpos($myvariable, '3') !== false) {
    echo "<br>I found my shipping method 2";
}
else {
    echo "<br>Not found 2";
}

php中的字符串pos不起作用

1 个答案: