Question

我在计算时间范围内的多个字段时遇到问题。我有下表：

# date, count, fb_user_count, email_user_count, reg_dt
'2015-10-27', '11', '6', '5', '2015-11-02 13:59:14'
'2015-10-26', '3', '1', '2', '2015-11-02 13:59:10'

我想获得每周注册类型的数量，例如：

# date, count, fb_user_count, email_user_count, reg_dt
'2015-11-02', '31', '16', '15', '2015-11-02 13:59:14'
'2015-11-09', '12', '6', '6', '2015-11-09 13:59:14'

每月：

# date, count, fb_user_count, email_user_count, reg_dt
'2015-11', '131', 'x', 'y', '2015-11-02 13:59:14' (the last value is not so important)
'2015-12', '112', 'x', 'y', '2015-12-09 13:59:14'

我尝试了不同的方法，但我很难完成这项任务。任何帮助都会很棒。谢谢！

Answer 1

您可以使用MySQL Date and Time functions WEEK()，MONTH()和YEAR()来构建查询：

SELECT
    MIN(date),
    SUM(count),
    SUM(fb_user_count),
    SUM(email_user_count)
FROM visit
GROUP BY WEEK(date, 1); -- First day is Monday

SELECT
    CONCAT(YEAR(date), '-', MONTH(date)),
    SUM(count),
    SUM(fb_user_count),
    SUM(email_user_count)
FROM visit
GROUP BY YEAR(date), MONTH(date);

Answer 2

对于您的每周报告（星期一），您可以使用

select subdate(min(date), 6-weekday(min(date))),
       sum(count), sum(fb_user_count), sum(email_user_count), max(reg_dt)
from tablename
group by subdate(date, 6-weekday(date));

以及您的月度报告

select concat(year(max(date), '-', month(max(date)),
       sum(count), sum(fb_user_count), sum(email_user_count), max(reg_dt)
from tablename
group by year(date), month(date);

选择计算时间范围内的多个字段 - MYSQL

2 个答案: