在我的应用中,我有一个文件上传控件,
<label>Upload File</label>
<div class="ui-select">
<input type="file" name="files" ng-files="getTheFiles($files)" />
</div>
有助于上传文件的控制器代码是......
$scope.file = null;
//UPLOAD FILE CODE
var formdata;
$scope.getTheFiles = function ($files) {
console.log($files[0].type);
formdata = new FormData();
angular.forEach($files, function (value, key) {
formdata.append(key, value);
});
};
// NOW UPLOAD THE FILES.
$scope.uploadFiles = function () {
var request = {
method: 'POST',
url: BasePath + 'uploadNative/UploadFiles/',
data: formdata,
headers: {
'Content-Type': undefined
}
};
// SEND THE FILES.
console.log(formdata);
if (formdata != null || formdata != undefined) {
$http(request)
.success(function (response) {
if (response != "Failed!" && response !="FileAlreadyUploaded") {
console.log("Succeeds");
}
else if(response == "FileAlreadyUploaded")
{
angular.element("#fileUploadModal").modal();
}
else {
console.log("Failed");
}
})
.error(function () {
});
}
我希望在成功或失败时清除文件上传控件,即
之后
angular.element("#fileUploadModal").modal();
显示模态,我希望清除控件。我该怎么办?请解释一下。
答案 0 :(得分:2)
将id
设为file upload control
HTML:
<input id= "control" type="file" name="files" ng-files="getTheFiles($files)" />
控制器:
angular.element("#control").value = "";
答案 1 :(得分:1)
添加 - 点击您的输入:
<input ng-click="reset()" id= "control" type="file" name="files" ng-files="getTheFiles($files)" />
并在控制器中创建重置方法:
$scope.reset= function () {
angular.element("input[type='file']").val(null);
};