我正在关注榆树教程Random,我一直试图一起跑两个骰子。
我修改了邮件以提供两个数字:
type Msg
= Roll
| NewFace Int Int
然后我需要生成在更新函数中发送消息的命令:
(model, Random.generate NewFace (Random.int 1 6))
问题在于,使用此构造失败:
-- error: Function `generate` is expecting 2 arguments, but was given 3.
(model, Random.generate NewFace (Random.int 1 6) (Random.int 1 6))
首先,我尝试用括号分组最后一个参数:
-- same error as before plus:
-- The type annotation is saying:
-- Msg -> Model -> ( Model, Cmd Msg )
-- But I am inferring that the definition has this type:
-- Msg -> Model -> ( Model, Cmd (Int -> Msg) )
(model, Random.generate NewFace ((Random.int 1 6) (Random.int 1 6)))
然后我发现有一个Random.pair
函数:
-- still complaining about update's signature and moreover
-- Function `generate` is expecting the 2nd argument to be:
-- Random.Generator Int
-- But it is:
-- Random.Generator ( Int, Int )
(model, Random.generate NewFace (Random.pair (Random.int 1 6) (Random.int 1 6)))
我确信我错过了一些微不足道的事情,虽然这是我与榆树的第一天,并且正在变得具有挑战性。
由于
答案 0 :(得分:8)
Random.pair
会生成一个元组,因此您的NewFace
消息必须接受元组作为参数。尝试将其更改为:
type Msg
= Roll
| NewFace (Int, Int)