Question

我正在使用codeigniter 3.0.4。这里这个动作发送到控制器（first.php）没有验证任何它将转向else语句并再次显示登录页面（设置为重定向（＆＃39;欢迎） / login_page＆＃39）;）。我的寄存器功能在同一个控制器上运行良好。什么是确切的问题..请帮助我找到它。谢谢。

..............控制器（first.php）.....

public function signup_validation(){
        $this->load->library('form_validation');

$this->form_validation->set_rules('email', 'Email',       'required|trim|xss_clean|valid_email|callback_validate_credentials');
$this->form_validation->set_rules('password', 'Password', 'required|md5|trim');

 if($this->form_validation->run() ){

$user_id= $this->model_users->get_id($this->input->post('email'));
$user_status = $this->model_users->get_status($this->input->post('email'));

$data = array (
      'user_id' => $user_id,
        'email' => $this->input->post('email'),
        'user_status' =>$user_status,
        'is_logged_in' => 1
    );

 $this->session->set_userdata($data);
}
      if ($this->session->userdata('user_status')=='0') {
    redirect('main/admins');
  }
  elseif ($this->session->userdata('user_status')=='1') {
    redirect('main/members');
  }else{

        redirect('welcome/login_page');
      }





 }

public function  validate_credentials(){

$this->load->model('model_users');

    if($this->model_users->can_log_in() ){

 return TRUE;
 } else {
$this->form_validation->set_message('validate_credentials', 'Invalid useername(email-id) or password. !');
return FALSE;
 }

}

....视图（login.php）......

                       echo form_open("first/signup_validation");
                   echo'<div class="row">';
                echo'<div class="form-group col-md-6 col-xs-12 col-sm-6">';
                echo'<label for="email">Email<span></span></label>';
                echo'<input type="text" class="form-control" id="email">';
                                        echo'</div>';
            echo'<div class="form-group col-md-6 col-xs-12 col-sm-6">';
            echo'<label for="password">Password<span></span></label>';
        echo'<input type="password" class="form-control" id="password">';
                                        echo'</div>';
                                    echo'</div>';


                                    $data2 = array(

                                        'class'       => 'btn btn-default',
                                    );

                                         echo form_submit($data2, 'Login');

                                 echo form_close('');
        ?>

Answer 1

public void UpdateDepartmentsSettings(DepatmentsSettingsDto depatmentsSettings)
{
    using (var transaction = new TransactionScope(TransactionScopeOption.RequiresNew
        , new TransactionOptions {IsolationLevel = IsolationLevel.Serializable}))
    {
        foreach (var departmentSetting in DepatmentsSettingsDto.DepartmentSettings)
        {
            var currentSetting = _context.DepartmentSettings.Find(departmentSetting.Id)
            if departmentSetting.Modified(currentSetting)
            {
                var newSetting = Mapper.Map<DepartmentSettingDto, DepartmentSetting>
                    (departmentSetting, currentSetting);
                Mapper.Map(currentSetting, newSetting);
            }
        }                
        _context.SaveChanges();
        transaction.Complete();
    }
}

您的echo '<input type="text" class="form-control" id="email">';元素不包含input属性。 name是用作验证规则中标识符的内容。

name

这样做......

$this->form_validation->set_rules('email'... // <- 'email' is the name attribute

codeigniter登录验证不验证规则

1 个答案: