Question

我知道我不能在回声中使用回声。我的PHP代码是：

echo '<img src="img/image1.jpg"

我想使用php变量作为源代码。有些想法：

echo '<img src="php-code"

Answer 1

使用。（点）你可以在echo语句中连接php变量。

echo '<img src="'.$src.'" />';

Answer 2

您有四种选择：

$url = '...';

//1
echo '<img src="' . $url . '">';

//2
echo "<img src='{$url}'>";        //Note that you have to use double quotes

//3
echo '<img src="';
echo $url;
echo '">';

//4
echo '<img src="', $url, '">';    //I would not recommend this one though

Answer 3

只是跳过第一个回声并在中间用回声写出html

<img src="<?=$src?>">

Answer 4

所有这些工作

echo '<img src="', $url, '">'; # This works by sending 3 different parameters to echo
echo '<img src="' . $url . '">'; # This works by concatenating 3 strings before echoing

echo '<img src="'; echo $url; echo '">'; # This works by echoing 3 strings in turn

echo "<img src=\"$url\">";   # All of these works by inserting
echo "<img src=\"${url}\">"; # the value of $url in the string
echo "<img src=\"{$url}\">"; # before echoing. " needs to be escaped.

# And finally, this (called HEREDOC) does the same thing as above
# only without ", so that sign is not needed to be escaped
echo <<<FOO
    <img src="$url">
    <img src="{$url}">
    <img src="${url}">
FOO;

Answer 5

有很多解决方案。我更喜欢这个：<?php echo '<img src="'.$url.'">'; ?> $ url代表Image-Url，我猜你知道ist。

你也可以这样做：例如：<img src="<?php echo $url; ?>"> 但我喜欢第一种方法，这是一种简单的方法来输出字符串。

echo

5 个答案: