由于某种原因sprintf打印我的char数组的名称，其内容我想附加一个字符串，使结果无效。它看起来没问题，应该有效，只有它没有。 这就是我所拥有的：
Before: name
After: nameST1
然后给了我：
Before:
After: ST1
{{1}}
请帮忙。
答案 0 :(得分：3)
您的第一个SELECT
CASE
When MM01.MM021_RATE = 1
Then ISNULL(PO101_EXT_COST, 0)*MM01.MM021_FOREIGN_RATE
Else ISNULL(PO101_EXT_COST, 0)*MM01.MM021_RATE
END AS Amt END AS Amount,
ISNULL(IN100_INV_CODE,'') AS [Item Code],
ISNULL(IN006_DESC,'') AS Major,
ISNULL(IN007_DESC,'') AS Minor,
ISNULL(IN100_DESC,'') AS Item,
ISNULL(PO100_PO_REQ, 0) AS [PO #],
ISNULL(PO100_EVT_ID, 0) AS [Ev ID],
ISNULL(EV200_EVT_DESC, '') AS [Ev Desc],
ISNULL(PO101_EXT_COST, 0) AS OriginalAmt,
ISNULL(PO101_PHASE, '') AS Phase,
ISNULL(PO101_STATUS, '') AS Status,
ISNULL(EV870_ACCT_SECURITY,'') AS [ARCtl],
ISNULL(PO102_ACCOUNT,'') AS [GL Account],
MM01.MM021_EFFECTIVE_DATE,
MM01.MM021_RATE,
MM01.MM021_FOREIGN_RATE,
(PO101_ORG_CODE) AS ORG,
(PO101_CURRENCY) AS Currency, (PO100_APPROVAL) AS Approval
FROM PO101_ORD_DTL
LEFT OUTER JOIN PO100_ORDERS ON
PO100_ORG_CODE = PO101_ORG_CODE AND
PO100_PO_REQ = PO101_PO_REQ
LEFT JOIN PO102_DISTR ON
PO102_ORG_CODE = PO101_ORG_CODE AND
PO102_PO_REQ = PO101_PO_REQ AND
PO102_PO_REQ_SEQ = PO101_ORD_SEQ
LEFT OUTER JOIN EV200_EVENT_MASTER ON
PO100_ORG_CODE = EV200_ORG_CODE AND
PO100_EVT_ID = EV200_EVT_ID
LEFT OUTER JOIN MM021_CURRENCY_RATES MM01 ON
PO101_CURRENCY = MM01.MM021_CODE
INNER JOIN
(SELECT MM021_CODE, MAX(MM021_EFFECTIVE_DATE) AS EFFECTIVE_DATE
FROM MM021_CURRENCY_RATES
WHERE MM021_FOREIGN_RATE > 0 AND MM021_TO_CODE = '***'
GROUP BY MM021_CODE) MM02 ON
MM01.MM021_CODE = MM02.MM021_CODE AND
MM01.MM021_EFFECTIVE_DATE = MM02.EFFECTIVE_DATE
LEFT OUTER JOIN IN100_INV_MASTER ON
PO101_ITEM = IN100_INV_CODE AND
PO101_ORG_CODE = IN100_ORG_CODE
LEFT OUTER JOIN IN007_MINOR_GROUP ON
IN100_ORG_CODE = IN007_ORG_CODE AND
IN100_MINOR = IN007_MINOR AND
IN100_MAJOR = IN007_MAJOR
LEFT JOIN IN006_MAJOR_GROUP ON
IN006_ORG_CODE = IN007_ORG_CODE AND
IN006_MAJOR = IN007_MAJOR
LEFT JOIN EV870_ACCT_MASTER ON
PO101_BILLTO=EV870_ACCT_CODE AND
PO101_ORG_CODE=EV870_ORG_CODE
WHERE
(PO101_ORG_CODE = '40' ) AND
(EV200_EVT_DESC = 'Tyrexpo India 2016') AND
(ISNULL(PO100_APPROVAL,'') IN ('A9')) AND
(ISNULL(PO101_STATUS, '') IN ('O','C','H')) AND
(ISNULL(PO101_PHASE, '') IN ('1')) AND
(PO101_TAX_RES_TYPE <> '8APGST')
调用Undefined Behavior，因为您没有初始化缓冲区。
你可以这样做：
printf或使用memset重置整个数组：
chat name[50] = {0};
关于第二个memset (name, 0x00, sizeof(name));
我想你没有发布你的真实代码。因此，发布代码不会导致printf成为第二个nameST1
答案 1 :(得分：2)
char name[]可以包含垃圾值。如图所示使用memset或初始化。
char name[50];
memset(name, 0, sizeof(name));
或使用
char name[50] = {0};