Question

我自己并没有真正做多少PHP，但我正在为我正在构建的UI创建一个php登录屏幕，以便从mysql数据库中将数据提取到一个表中。我有表格连接到数据库正常和一般屏幕工作，但我遇到登录屏幕的问题。

目前我想要的是login.php页面接受正确的凭据并将用户引导到index.php页面。

index.php页面包含

include('session.php');    //include login session

例如，我不断收到以下两个错误

注意：未定义索引：活动
致命错误：调用未定义的函数session_register（）

以下是我的login.php页面的代码

<?php

   include("config.php");
   session_start();
   $error=''; // Variable To Store Error Message

   if($_SERVER["REQUEST_METHOD"] == "POST") {
      // username and password sent from form 

      $myusername = mysqli_real_escape_string($db,$_POST['username']);
      $mypassword = mysqli_real_escape_string($db,$_POST['password']); 

      $sql = "SELECT user_id FROM admin_tbl WHERE username = '$myusername' and password = '$mypassword'";
      $result = mysqli_query($db,$sql) or die("Error: ".mysqli_error($db));

      $row = mysqli_fetch_array($result,MYSQLI_ASSOC);

      $active = $row['active'];

      $count = mysqli_num_rows($result);

      // If result matched $myusername and $mypassword, table row must be 1 row

      if($count == 1) {
         // Register $myusername, $mypassword and redirect to file "index.php"
         session_register("username");
         session_register("password");
         $_SESSION['login_user'] = $myusername;

         header("location: index.php");
      }else {
         $error = "Your Username Name or Password is invalid";
      }
   }
?>

此处还有我的config.php

$mysql_hostname = "localhost";  //your mysql host name
$mysql_user = "adminTest";          //your mysql user name
$mysql_password = "badgerBadger";           //your mysql password
$mysql_database = "mushroom";   //your mysql database

$db = new mysqli($mysql_hostname, $mysql_user, $mysql_password, $mysql_database);
//mysql_select_db($mysql_database, $bd) or die("Error on database connection");
  if($db->connect_errno > 0){
      die('Unable to connect to database [' . $db->connect_error . ']');
  }

这是我的session.php文件的代码

<?php

   include('config.php');
   session_start();

   $user_check = $_SESSION['login_user'];
   $ses_sql = mysqli_query($db,"SELECT * FROM admin_tbl WHERE username = '$myusername' and password = '$mypassword'");
   $login_session =$row['first'];
   $row = mysqli_fetch_array($ses_sql,MYSQLI_ASSOC);

   $login_session = $row['username'];

   if(!isset($_SESSION['login_user'])){
      header("location:login.php");
   }

?>

任何帮助都将非常感谢，提前感谢:)

变化

更新了代码以删除与表查询相关的拼写错误，并解决了其他一些问题。

更新了login.php代码以进行正确的通话

新错误#######

session.php中未定义的变量用户名
session.php中未定义的可变密码
session.php第22行中未定义的变量行

奇怪的是解析变量并重定向到index.php页面。我试过做的是将这些变量的值设置为空白或$ myusername＆＃34; ＆＃34 ;;例如。这确实消除了用户名和密码的错误，但它仍然抱怨session.php文件中的第24行= $ login_session = $ row [＆＃39; first＆＃39;]; 抱怨它是一个非法的字段串，当它实际上是一个有效的字段时。

TABLENAME admin_tbl ###下面的字段

USER_ID
t_date
第一
最后
用户名
密码
电子邮件
活性

Answer 1

在配置

中使用此代码

$db= mysqli_connect("localhost", "adminTest", "badgerBadger","mushroom")or die("cannot connect....");

Answer 2

确保您的数据库字段名称与查询字段相同，并且数据库中至少有一条记录...并且只检查您的数据库连接

     $result = mysqli_query($db,$sql) or die("Error: ".mysqli_error($db));

执行此操作并检查错误位置

Answer 3

Nick, here is your correct code. 
1. Notice: Undefined index: active - error because of you are try to fetch only user_id from your database.so you have to use "SELECT * FROM " or "SELECT user_id,active FROM "
2. Fatal error: Call to undefined function session_register() - you can login and create session without use of session_register() no need of session register
session_start();
   include("config.php");
   $error=''; // Variable To Store Error Message
   $active = '';
   if($_SERVER["REQUEST_METHOD"] == "POST") {
      // username and password sent from form 

      $myusername = mysqli_real_escape_string($db,$_POST['username']);
      $mypassword = mysqli_real_escape_string($db,$_POST['password']); 
      $sql = "SELECT * FROM admin_tbl WHERE username = '$myusername' and password = '$mypassword'";
      //$sql = "SELECT user_id,active FROM admin_tbl WHERE username = '$myusername' and password = '$mypassword'";
      $result = mysqli_query($db,$sql) or die("Error: ".mysqli_error($db));

      $row = mysqli_fetch_array($result,MYSQLI_ASSOC);

      $active = $row['active'];

      $count = mysqli_num_rows($result);

      // If result matched $myusername and $mypassword, table row must be 1 row

      if($count == 1) {
         // Register $myusername, $mypassword and redirect to file "index.php"
         //session_register("username");
         //session_register("password");
         $_SESSION['login_user'] = $myusername;

         header("location: index.php");
      }else {
         $error = "Your Username Name or Password is invalid";
      }
   }

Answer 4

Nick，这是“session.php”的新代码。

session_start(); // always start session before write any code.its good to       start session before database connection
include('config.php');
if(!(isset($_SESSION["login_user"]) && isset($_SESSION["password"]))){
    include("login.php");
}
else{
    $myusername=$_SESSION['login_user'];
    $mypassword=$_SESSION['password'];
}
$ses_sql = mysqli_query($db,"SELECT * FROM admin_tbl WHERE username = '$myusername' and password = '$mypassword'");
$row = mysqli_fetch_array($ses_sql);
$login_session =$row['first'];
//$row = mysqli_fetch_array($ses_sql,MYSQLI_ASSOC); "always define variable before using that variable  "

$username_session = $row['username'];

And also after this line 
$_SESSION["login_user"] = $myusername; 
you have to add following code in login.php

$_SESSION["password"] = $row['password'];

BTW its not good practice to use password on session.

将我的php登录屏幕连接到我的SQL DB

TABLENAME admin_tbl ###下面的字段

4 个答案: