Question

我创建了一个用于教育目的的简单项目，因此我有一个主要功能和3个特征Battery，Display和GSM以及它们的实现。我希望main函数位于文件main.rs和另外一个名为phone.rs的文件中的3个特征：

phone.rs

mod phone{
    pub struct Battery{
        model : String,
        hours_idle : i16,
        hours_talk : i16
    }

    pub struct Display{
        size : i16,
        number_of_colors : i32
    }

    pub struct GSM{
        model : String,
        manufactor : String,
        price : f32,
        owner : String,
        battery: Battery,
        display : Display
    }

     impl Battery {
        pub fn new(model : String, hours_idle : i16, hours_talk : i16) -> Battery{
            Battery {model : model, hours_idle : hours_idle ,hours_talk : hours_talk}
        }
        pub fn print(&self){
            println!("Battery model: {}", self.model);
            println!("Hours idle: {}", self.hours_idle);
            println!("hours talk: {}", self.hours_talk);
        }
    }

    impl Display {
        pub fn new(size: i16, number_of_colors : i32) -> Display{
            Display{size : size, number_of_colors : number_of_colors}
        }
        pub fn print(&self){
            println!("size: {}", self.size);
            println!("number_of_colors: {}", self.number_of_colors);
        }
    }

     impl GSM {
        pub fn new(model : String, manufactor : String, price : f32, owner : String, battery : Battery, display : Display) -> GSM{
            GSM{model : model, manufactor : manufactor, price : price, owner : owner, battery : battery, display : display }
        }
        pub fn print(&self){
            println!("Model: {}, Manufactor: {}", self.model, self.manufactor);
            println!("price: {}", self.price);
            println!("owner: {}", self.owner);
            self.battery.print();
            self.display.print();
        }
    }
}

main.rs

pub mod phone;
fn main(){
    let battey = phone::Battery::new("modelBattery".to_string(), 1,2);
    let display =  phone::Display::new(10,20);
    //model : String, manufactor : String, price : f32, owner : String, baterry : Battery, display : Display
    let gsm =  phone::GSM::new("modelPhone".to_string(), "manufactor".to_string(), 100.0, "owner".to_string(), battey, display);
    gsm.print();
}

首先，所有内容都在一个文件（main.rs）中，一切正常（例如，我在phone::，Display和GSM前添加了Battery。在main.rs中{1}}，当我移动特征并在phone.rs中添加mod phone{}，在main.rs中添加pub mod phone时，我从编译器中得到以下错误：

src\main.rs:3:18: 3:37 error: failed to resolve. Could not find `Battery` in `phone` [E0433]
src\main.rs:3     let battey = phone::Battery::new("modelBattery".to_string(), 1,2);
                               ^~~~~~~~~~~~~~~~~~~
src\main.rs:3:18: 3:37 help: run `rustc --explain E0433` to see a detailed explanation
src\main.rs:3:18: 3:37 error: unresolved name `phone::Battery::new` [E0425]
src\main.rs:3     let battey = phone::Battery::new("modelBattery".to_string(), 1,2);
                               ^~~~~~~~~~~~~~~~~~~
src\main.rs:3:18: 3:37 help: run `rustc --explain E0425` to see a detailed explanation
src\main.rs:4:20: 4:39 error: failed to resolve. Could not find `Display` in `phone` [E0433]
src\main.rs:4     let display =  phone::Display::new(10,20);
                                 ^~~~~~~~~~~~~~~~~~~
src\main.rs:4:20: 4:39 help: run `rustc --explain E0433` to see a detailed explanation
src\main.rs:4:20: 4:39 error: unresolved name `phone::Display::new` [E0425]
src\main.rs:4     let display =  phone::Display::new(10,20);
                                 ^~~~~~~~~~~~~~~~~~~
src\main.rs:4:20: 4:39 help: run `rustc --explain E0425` to see a detailed explanation
src\main.rs:6:16: 6:31 error: failed to resolve. Could not find `GSM` in `phone` [E0433]
src\main.rs:6     let gsm =  phone::GSM::new("modelPhone".to_string(), "manufactor".to_string(), 100.0, "owner".to_string(), battey, display);
                             ^~~~~~~~~~~~~~~
src\main.rs:6:16: 6:31 help: run `rustc --explain E0433` to see a detailed explanation
src\main.rs:6:16: 6:31 error: unresolved name `phone::GSM::new` [E0425]
src\main.rs:6     let gsm =  phone::GSM::new("modelPhone".to_string(), "manufactor".to_string(), 100.0, "owner".to_string(), battey, display);
                             ^~~~~~~~~~~~~~~
src\main.rs:6:16: 6:31 help: run `rustc --explain E0425` to see a detailed explanation
src\main.rs:7:5: 7:16 error: the type of this value must be known in this context
src\main.rs:7     gsm.print();

我不理解他们，我在这里和谷歌搜索，但我找不到解决方案。另外，我得到很多警告，电话中的方法永远不会被使用#[warn(dead_code)]，任何帮助都会受到赞赏。

Answer 1

简答：您不需要mod phone中的phone.rs。只需删除它，您的代码就可以工作（假设代码的其余部分是正确的）。

更长的答案：main.rs中的以下代码：

pub mod phone;

相当于：

pub mod phone {
    // literally insert the contents of phone.rs here
}

因此您无需将phone.rs中的所有内容都包含在mod phone {}中。

您当前的代码转换为：

pub mod phone {
    pub mod phone {
        pub struct Battery { ... }
        ...
    }
}

这意味着您需要在Battery中以phone::phone::Battery {和Display作为phone::phone::Display等方式访问main.rs。

无法理解Rust模块系统

1 个答案: