大家好我正在尝试使用angular JS构建一个测验应用程序,我有两个表问题和答案,代码如下
public class Question
{
public int QuestionID { get; set; }
public string QuestionName { get; set; }
public List<Options> Options = new List<Options>();
}
public class Options
{
public int AnswerId { get; set; }
public int QuestionID { get; set; }
public string Answer { get; set; }
public bool isAnswer { get; set; }
}
public static class QuizDetails
{
public static string GetQuiz()
{
Dictionary<int, List<Question>> displayQuestion = new Dictionary<int, List<Question>>();
//List<Quiz> quiz = new List<Quiz>();
//Options op1 = new Options();
dbDataContext db = new dbDataContext();
var v = (from op in db.QUESTIONs
join pg in db.ANSWERs on op.QUESTION_ID equals pg.QUESTION_ID
select new { Id = op.QUESTION_ID, Name = op.QUESTION_NAME, pg.ANSWER_ID, pg.QUESTION_ID, pg.ANSWER_DESCRIPTION, pg.CORRECT_ANSWER }).ToList();
return JsonConvert.SerializeObject(v);
}
}
这是我构建应用程序的参考代码 http://www.codeproject.com/Articles/860024/Quiz-Application-in-AngularJs,如何根据JS文件中编写的代码返回JSON格式可以帮助我
答案 0 :(得分:1)
现在GetQuiz
返回表示对象的字符串。您的客户端并不真正知道字符串包含什么,它只是将其作为普通字符串处理。
您可以以其他方式返回,例如:
return new HttpResponseMessage
{
Content = new StringContent(
JsonConvert.SerializeObject(v),
System.Text.Encoding.UTF8,
"application/json")
};
如果您想继续将其作为字符串返回,则必须在客户端中手动反序列化它:
var object = angular.fromJson(returnedData);