Question

我的问题是添加到JSON逻辑中的以下post here的变体。我使用的是PHP 5.6.22

我需要在runtim上构建一个没有对象的类来构建一个返回给客户端的相同类型的JSON对象。我的代码：

ApplyPagingAndSorting()

运行时，我收到以下错误：

public static function getData()
{
    $columns = array ("Name", "Address", "Age" );
    $values  = array ("John", "A Ave 222", 32 );

    $ret = (object)[];
    $index = 0;

    foreach ($columns as $col)
    {
        $value = $values[$index++];
        $ret[] = (object) [$col => $value]; // Error here
    }

    return json_encode($ret);
}

帮助解决这个问题......

Answer 1

在PHP中，您可以通过设置

将新属性添加到数组

$columns = array ("Name", "Address", "Age" );
$values  = array ("John", "A Ave 222", 32 );

$ret = (object) [];
$index = 0;

foreach ($columns as $col)
{
    $value = $values[$index++];
    // You can create and add new property to object in php by such way
    $ret->$col = $value; 
}

echo json_encode($ret);  // {"Name":"John","Address":"A Ave 222","Age":32}

Answer 2

怎么样：

public static function getData()
{
    $data = [
        "Name" => "John",
        "Address" => "A Ave 222",
        "Age" => 32,
    ];
    return json_encode($data);
}

没有类的对象：添加新字段并返回JSON

2 个答案: