Question

我正在构建一个用户可以编辑信息的平台。这包括一张图片。它可以在更换图片时起作用，但如果用户没有添加新图片并希望保留旧图片，则图片会消失并在数据库中填入空白，而不是保留已存在的图片。

    <?
if(isset($_POST['submit']))
{
    # Define all the standard values that were created in the form
    $picture = $_FILES['file']['name'];
    $name = $_POST['name'];
    $description = $_POST['description'];
    $tags = $_POST['tags'];
    $color = $_POST['color'];
    $xs = $_POST['xs'];
    $s = $_POST['s'];
    $m = $_POST['m'];
    $l = $_POST['l'];
    $xl = $_POST['xl'];
    $xxl = $_POST['xxl'];
    $price = $_POST['price'];
    $sale = $_POST['sale'];
    $gender = $_POST['gender'];
    # checking the sizes and adjusting the values accordingly
    if ($xs=="on"){$xs="true";}else{$xs="false";};
    if ($s=="on"){$s="true";}else{$s="false";};
    if ($m=="on"){$m="true";}else{$m="false";};
    if ($l=="on"){$l="true";}else{$l="false";};
    if ($xl=="on"){$xl="true";}else{$xl="false";};
    if ($xxl=="on"){$xxl="true";}else{$xxl="false";};
    #defining the $size
    $sizes = $xs."&".$s."&".$m."&".$l."&".$xl."&".$xxl;
    #handling the picture that was uploaded
    if(isset($_FILES['file']))
    {
        #Putting all the information into the database
        move_uploaded_file($_FILES['file']['tmp_name'], '../upload/'.$picture);
        $todo = "INSERT INTO PRODUCTS values('','$name','$picture','$description','$tags','$color','$sizes','$price','$sale','$gender')";
        if (mysqli_query($con,$todo))
        {
            $notice = "The product has been added to the product list";
        }
        else
        {
            $notice = "The data could not be handled, please try again";
        }
    }
    else
    {
        $notice = "The picture could not be handled, please try again";
    };
}
?>

编辑：添加了整个代码

同样快速的旁注，我是一名学生，我并没有真正得到过于复杂的代码（但是）所以如果你带来一个20行的解决方案，我可能不会得到它，也不会从中学到东西＆gt; ＆LT;

Answer 1

您可以像这样检查文件上传：

if( !file_exists( $_FILES['file']['name'] ) || !is_uploaded_file( $_FILES['file']['name'] ) ) {

    // Nothing uploaded ...

}

PHP变量没有被收集的内容替换

1 个答案: