Question

在我的数据库中有4名学生：

1st Student's created_at = 2016-05-12 02:23:51

2nd Student's created_at = 2016-05-27 07:37:45

3rd Student's created_at = 2016-05-29 07:40:29

4th Student's created_at = 2016-05-29 07:50:05

为什么我的代码只返回第一个学生？

$students = Student::select('id as ID_NO', 'fname as Firstname', 'lname as Lastname', 'created_at')
                             ->whereBetween('created_at', 
                              [Carbon::createFromDate(2016, 5, 12)->toDateString(),
                               Carbon::createFromDate(2016, 5, 27)->toDateString()])

应该退回第一和第二名学生。 “to”部分是否包含在WhereBetween或我的代码中有什么问题？

我需要你的帮助。提前谢谢！

Answer 1

对于那些最终到这里并希望得到问题答案的人（如果它已更新......＆＃34; Laravel包含哪些内容？＆＃34;）：

是

Answer 2

Laravel搜索between，这意味着它会获得2016-05-12 00:00:00和2016-05-27 00:00:00之间的所有行。您的第二个用户是在2016-05-27 07:37:45创建的，这超出了范围，因此Laravel无法获取它。

使用此功能并尝试以下方法：

$students = Student::select('id as ID_NO', 'fname as Firstname', 'lname as Lastname', 'created_at')
                             ->whereBetween('created_at', 
                              [Carbon::createFromDate(2016, 5, 12)->toDateString(),
                               Carbon::createFromDate(2016, 5, 28)->toDateString()])

希望这有效！

Answer 3

您需要格式化created_at到Y-m-d格式。请参阅更改：

$students = Student::select('id as ID_NO', 'fname as Firstname', 'lname as Lastname', 'created_at')
                                 ->whereBetween(DB::raw('date(created_at)'), 
                                  [Carbon::createFromDate(2016, 5, 12)->toDateString(),
                                   Carbon::createFromDate(2016, 5, 27)->toDateString()])

Answer 4

快速解决方案

$students = Student::select('id as ID_NO', 'fname as Firstname', 'lname as Lastname', 'created_at')
                             ->whereBetween(DB::raw('date(created_at)'), 
                              [Carbon::createFromDate(2016, 5, 12)->toDateString(),
                               Carbon::createFromDate(2016, 5, 27)->toDateString()])

在laravel包含之间的哪个位置？

4 个答案: