Question

当我点击链接时，我想在我的“JobDownload”servlet中调用我的API，并将响应作为文件下载到浏览器中。 API返回一个多部分响应，我将其转换为输入流。我可以在下面的console.log（）中调用servlet后显示返回的内容，但无法打开浏览器下载框。

我这样称呼：

$("#filename").click(function(){
    alert("Download initiated");
    $.get('jobDownload', {'key': jobDownId,'name':jobFileName}, 
        function (data) {
           console.log("Data Downloaded"+data);                                
         });
});

我的servlet看起来像这样：

 protected void processRequest(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {

        String jobId = request.getParameter("key");
        String fileName = request.getParameter("name");

        String headerKey = "Content-Disposition";
        String headerValue = String.format("attachment; filename=\"%s\"", fileName);
        response.setHeader(headerKey, headerValue);
        response.setContentType("text/plain");

        System.out.println("\n\nJob ID is :"+jobId+"\nFilename is :"+fileName);

        // Calling my API which will return an InputStream
        InputStream jobResult = getJobResultById(jobId);

        OutputStream os = response.getOutputStream();
        System.out.println("\n\nInputStream of job is here");

        // Stream the inputStream to outputStream
        streamOutput(jobResult, os);
        System.out.println("\n\nOutStream of job is here");
    }

我的streamOutput方法是这样的：

public void streamOutput(InputStream is, OutputStream os) {
        BufferedInputStream dis = null;
        try {
            dis = new BufferedInputStream(new DataInputStream(is));
            byte[] buf = new byte[8192];
            int nread = dis.read(buf);
            while (nread != -1) {
                os.write(buf, 0, nread);
                nread = dis.read(buf);
            }
            // flush the output as soon as possible to prevent client timeouts
            // we can delay cleaning up the inputstream 
            os.flush();
        } catch (IOException ioe) {
            ioe.printStackTrace();
        }
        dis = null;
    }

我没有得到用户应该点击下载此结果的浏览器下载对话框。我是否需要在Jquery方法中添加任何内容或在我的java代码中添加内容

提示浏览器下载文件throgh Jquery

0 个答案: