Question

我正在编写一个解析器（用于学习pourpuses）。

我希望它解析像

这样的结构

let myVar be 40 plus 2

和

let myVar be (40 plus 2)

没有问题......但我的解析器并没有“理解”前者。它看到40并认为“好吧，它是Literal Numeric 40”。

当我放括号时，我的解析器效果很好。

我很难理解为什么。

分析器：

type value =
    | Boolean of bool
    | Numeric of float
    | String of string

type arithmetic = Sum | Sub | Mul | Div | Pow

type logic = And | Or | Equal | NotEqual | Greater | Smaller

type identifier =
    | Identifier of string

type expression =
    | Literal of value
    | Arithmetic of expression * arithmetic * expression
    | Negative of expression
    | Negation of expression
    | Logic of expression * logic * expression
    | Variable of identifier

type statement =
    | Assignment of identifier * expression
    | Print of expression
    | Read of identifier

let private ws = spaces

let private str s = pstring s .>> ws

let private pnumeric =
    pfloat
    .>> ws
    |>> fun n -> Literal (Numeric n)

let private pboolean =
    choice [
        (stringReturn "true" (Literal (Boolean true)))
        (stringReturn "false" (Literal (Boolean false)))
    ]
    .>> ws

let private pstringliteral =
    choice [
        between (pstring "\"") (pstring "\"") (manyChars (satisfy (fun c -> c <> '"')))
        between (pstring "'") (pstring "'") (manyChars (satisfy (fun c -> c <> ''')))
    ]
    |>> fun s -> Literal (String s)

let private pidentifier =
    many1Satisfy2L isLetter (fun c -> isLetter c || isDigit c) "identifier"
    |>> fun s -> Identifier s

let private betweenParentheses p =
    between (str "(") (str ")") p

let private pvalue =
    choice [
        pnumeric
        pboolean
    ]

let private prefixOperator (p: OperatorPrecedenceParser<_,_,_>) op prec map =
    p.AddOperator(PrefixOperator (op, ws, prec, true, map))

let private infixOperator (p: OperatorPrecedenceParser<_,_,_>) op prec map =
    p.AddOperator(InfixOperator (op, ws, prec, Associativity.Left, map))

let private oppNegation = new OperatorPrecedenceParser<_,_,_>()
let private oppLogic = new OperatorPrecedenceParser<_,_,_>()
let private oppArithmetic = new OperatorPrecedenceParser<_,_,_>()
let private oppNegative = new OperatorPrecedenceParser<_,_,_>()

prefixOperator oppNegation "not" 1 (fun x -> Negation x)
infixOperator oppLogic "is" 1 (fun x y -> Logic (x, Equal, y))
infixOperator oppLogic "isnt" 1 (fun x y -> Logic (x, NotEqual, y))
infixOperator oppLogic "and" 2 (fun x y -> Logic (x, And, y))
infixOperator oppLogic "or" 3 (fun x y -> Logic (x, Or, y))
prefixOperator oppNegative "-" 1 (fun x -> Negative x)
infixOperator oppArithmetic ">" 1 (fun x y -> Logic (x, Greater, y))
infixOperator oppArithmetic "<" 1 (fun x y -> Logic (x, Smaller, y))
infixOperator oppArithmetic "is" 2 (fun x y -> Logic (x, Equal, y))
infixOperator oppArithmetic "isnt" 2 (fun x y -> Logic (x, NotEqual, y))
infixOperator oppArithmetic "plus" 3 (fun x y -> Arithmetic (x, Sum, y))
infixOperator oppArithmetic "minus" 3 (fun x y -> Arithmetic (x, Sub, y))
infixOperator oppArithmetic "times" 4 (fun x y -> Arithmetic (x, Mul, y))
infixOperator oppArithmetic "divided by" 4 (fun x y -> Arithmetic (x, Div, y))
infixOperator oppArithmetic "power" 5 (fun x y -> Arithmetic (x, Pow, y))

let private negationExprParser = oppNegation.ExpressionParser
let private logicExprParser = oppLogic.ExpressionParser
let private arithmeticExprParser = oppArithmetic.ExpressionParser
let private negativeExprParser = oppNegative.ExpressionParser

oppNegation.TermParser <- choice [
    betweenParentheses negationExprParser
    pboolean
]

oppLogic.TermParser <- choice [
    betweenParentheses logicExprParser
    pboolean
]

oppNegative.TermParser <- choice [
    betweenParentheses negativeExprParser
    pnumeric
]

oppArithmetic.TermParser <- choice [
    betweenParentheses arithmeticExprParser
    pnumeric
]

let private pexpression =
    choice [
        attempt <| pstringliteral
        attempt <| negationExprParser
        attempt <| logicExprParser
        attempt <| negativeExprParser
        attempt <| arithmeticExprParser
        attempt <| (pidentifier |>> fun id -> Variable id)
    ]

let private passignment =
    pipe2 (str "let" .>> ws >>. pidentifier) (ws >>. str "be" >>. ws >>. pexpression) (fun id exp -> Assignment (id, exp))

let private pprint =
    str "print"
    >>. pexpression
    |>> fun exp -> Print exp

let private pread =
    str "read"
    >>. pidentifier
    |>> fun id -> Read id

let private pstatement =
    choice [
        passignment
        pprint
        pread
    ]

let private pline =
    skipMany (satisfy (fun c -> c = '\n' || c = ' '))
    >>. pstatement
    .>> ws

let private pcode =
    many pline

let generateAST code =
    match run pcode code with
    | Success (ast, _, _) -> sprintf "%A" ast
    | Failure (msg, _, _) -> msg

用法：

[<EntryPoint>]
let main argv =
    printfn "%s\n" (generateAST "let b be 5 plus 7") 
    // [Assignment (Identifier "b",Literal (Numeric 5.0))]

    printfn "%s\n" (generateAST "let b be (5 plus 7)")
    // [Assignment
    //    (Identifier "b",Arithmetic (Literal (Numeric 5.0),Sum,Literal (Numeric 7.0)))]

    0

Answer 1

查看FParsec - Tracing a parser

如果您将推荐的FParsec跟踪功能添加到代码顶部

let (<!>) (p: Parser<_,_>) label : Parser<_,_> =
    fun stream ->
        printfn "%A: Entering %s" stream.Position label
        let reply = p stream
        printfn "%A: Leaving %s (%A)" stream.Position label reply.Status
        reply

然后修改解析器以使用跟踪功能

let private pnumeric =
    (pfloat
    .>> ws
    |>> fun n -> Literal (Numeric n)) <!> "pnumeric"

let private pboolean =
    (choice [
        (stringReturn "true" (Literal (Boolean true)))
        (stringReturn "false" (Literal (Boolean false)))
    ]
    .>> ws) <!> "pboolean"

let private pstringliteral =
    (choice [
        between (pstring "\"") (pstring "\"") (manyChars (satisfy (fun c -> c <> '"')))
        between (pstring "'") (pstring "'") (manyChars (satisfy (fun c -> c <> ''')))
    ]
    |>> fun s -> Literal (String s))  <!> "pstringliteral"

let private pidentifier =
    (many1Satisfy2L isLetter (fun c -> isLetter c || isDigit c) "identifier"
    |>> fun s -> Identifier s) <!> "pidentifier"

let private betweenParentheses p =
    (between (str "(") (str ")") p) <!> "betweenParentheses"

let private pvalue =
    (choice [
        pnumeric
        pboolean
    ]) <!> "pvalue"

let private negationExprParser = oppNegation.ExpressionParser <!> "negationExprParser"
let private logicExprParser = oppLogic.ExpressionParser <!> "logicExprParser"
let private arithmeticExprParser = oppArithmetic.ExpressionParser <!> "arithmeticExprParser"
let private negativeExprParser = oppNegative.ExpressionParser <!> "negativeExprParser "

let private pexpression =
    choice [
        attempt <| pstringliteral
        attempt <| negationExprParser
        attempt <| logicExprParser
        attempt <| negativeExprParser
        attempt <| arithmeticExprParser
        attempt <| (pidentifier |>> fun id -> Variable id)
    ]  <!> "pexpression"

let private passignment =
    pipe2 (str "let" .>> ws >>. pidentifier) (ws >>. str "be" >>. ws >>. pexpression) (fun id exp -> Assignment (id, exp))  <!> "passignment"

let private pprint =
    (str "print"
    >>. pexpression
    |>> fun exp -> Print exp)  <!> "pprint"

let private pread =
    (str "read"
    >>. pidentifier
    |>> fun id -> Read id)  <!> "pread"

let private pstatement =
    (choice [
        passignment
        pprint
        pread
    ])   <!> "pstatement"

let private pline =
    (skipMany (satisfy (fun c -> c = '\n' || c = ' '))
    >>. pstatement
    .>> ws)   <!> "pline"

let private pcode =
    many pline  <!> "pcode"

并运行您将获得的代码

(Ln: 1, Col: 1): Entering pcode
(Ln: 1, Col: 1): Entering pline
(Ln: 1, Col: 1): Entering pstatement
(Ln: 1, Col: 1): Entering passignment
(Ln: 1, Col: 5): Entering pidentifier
(Ln: 1, Col: 6): Leaving pidentifier (Ok)
(Ln: 1, Col: 10): Entering pexpression
(Ln: 1, Col: 10): Entering pstringliteral
(Ln: 1, Col: 10): Leaving pstringliteral (Error)
(Ln: 1, Col: 10): Entering negationExprParser
(Ln: 1, Col: 10): Entering betweenParentheses
(Ln: 1, Col: 10): Leaving betweenParentheses (Error)
(Ln: 1, Col: 10): Entering pboolean
(Ln: 1, Col: 10): Leaving pboolean (Error)
(Ln: 1, Col: 10): Leaving negationExprParser (Error)
(Ln: 1, Col: 10): Entering logicExprParser
(Ln: 1, Col: 10): Entering betweenParentheses
(Ln: 1, Col: 10): Leaving betweenParentheses (Error)
(Ln: 1, Col: 10): Entering pboolean
(Ln: 1, Col: 10): Leaving pboolean (Error)
(Ln: 1, Col: 10): Leaving logicExprParser (Error)
(Ln: 1, Col: 10): Entering negativeExprParser
(Ln: 1, Col: 10): Entering betweenParentheses
(Ln: 1, Col: 10): Leaving betweenParentheses (Error)
(Ln: 1, Col: 10): Entering pnumeric
(Ln: 1, Col: 12): Leaving pnumeric (Ok)
(Ln: 1, Col: 12): Leaving negativeExprParser (Ok)
(Ln: 1, Col: 12): Leaving pexpression (Ok)
(Ln: 1, Col: 12): Leaving passignment (Ok)
(Ln: 1, Col: 12): Leaving pstatement (Ok)
(Ln: 1, Col: 12): Leaving pline (Ok)
(Ln: 1, Col: 12): Entering pline
(Ln: 1, Col: 12): Entering pstatement
(Ln: 1, Col: 12): Entering passignment
(Ln: 1, Col: 12): Leaving passignment (Error)
(Ln: 1, Col: 12): Entering pprint
(Ln: 1, Col: 12): Leaving pprint (Error)
(Ln: 1, Col: 12): Entering pread
(Ln: 1, Col: 12): Leaving pread (Error)
(Ln: 1, Col: 12): Leaving pstatement (Error)
(Ln: 1, Col: 12): Leaving pline (Error)
(Ln: 1, Col: 12): Leaving pcode (Ok)
[Assignment (Identifier "b",Literal (Numeric 5.0))]

(Ln: 1, Col: 1): Entering pcode
(Ln: 1, Col: 1): Entering pline
(Ln: 1, Col: 1): Entering pstatement
(Ln: 1, Col: 1): Entering passignment
(Ln: 1, Col: 5): Entering pidentifier
(Ln: 1, Col: 6): Leaving pidentifier (Ok)
(Ln: 1, Col: 10): Entering pexpression
(Ln: 1, Col: 10): Entering pstringliteral
(Ln: 1, Col: 10): Leaving pstringliteral (Error)
(Ln: 1, Col: 10): Entering negationExprParser
(Ln: 1, Col: 10): Entering betweenParentheses
(Ln: 1, Col: 11): Entering negationExprParser
(Ln: 1, Col: 11): Entering betweenParentheses
(Ln: 1, Col: 11): Leaving betweenParentheses (Error)
(Ln: 1, Col: 11): Entering pboolean
(Ln: 1, Col: 11): Leaving pboolean (Error)
(Ln: 1, Col: 11): Leaving negationExprParser (Error)
(Ln: 1, Col: 11): Leaving betweenParentheses (Error)
(Ln: 1, Col: 11): Leaving negationExprParser (Error)
(Ln: 1, Col: 10): Entering logicExprParser
(Ln: 1, Col: 10): Entering betweenParentheses
(Ln: 1, Col: 11): Entering logicExprParser
(Ln: 1, Col: 11): Entering betweenParentheses
(Ln: 1, Col: 11): Leaving betweenParentheses (Error)
(Ln: 1, Col: 11): Entering pboolean
(Ln: 1, Col: 11): Leaving pboolean (Error)
(Ln: 1, Col: 11): Leaving logicExprParser (Error)
(Ln: 1, Col: 11): Leaving betweenParentheses (Error)
(Ln: 1, Col: 11): Leaving logicExprParser (Error)
(Ln: 1, Col: 10): Entering negativeExprParser
(Ln: 1, Col: 10): Entering betweenParentheses
(Ln: 1, Col: 11): Entering negativeExprParser
(Ln: 1, Col: 11): Entering betweenParentheses
(Ln: 1, Col: 11): Leaving betweenParentheses (Error)
(Ln: 1, Col: 11): Entering pnumeric
(Ln: 1, Col: 13): Leaving pnumeric (Ok)
(Ln: 1, Col: 13): Leaving negativeExprParser (Ok)
(Ln: 1, Col: 13): Leaving betweenParentheses (Error)
(Ln: 1, Col: 13): Leaving negativeExprParser (Error)
(Ln: 1, Col: 10): Entering arithmeticExprParser
(Ln: 1, Col: 10): Entering betweenParentheses
(Ln: 1, Col: 11): Entering arithmeticExprParser
(Ln: 1, Col: 11): Entering betweenParentheses
(Ln: 1, Col: 11): Leaving betweenParentheses (Error)
(Ln: 1, Col: 11): Entering pnumeric
(Ln: 1, Col: 13): Leaving pnumeric (Ok)
(Ln: 1, Col: 18): Entering betweenParentheses
(Ln: 1, Col: 18): Leaving betweenParentheses (Error)
(Ln: 1, Col: 18): Entering pnumeric
(Ln: 1, Col: 19): Leaving pnumeric (Ok)
(Ln: 1, Col: 19): Leaving arithmeticExprParser (Ok)
(Ln: 1, Col: 20): Leaving betweenParentheses (Ok)
(Ln: 1, Col: 20): Leaving arithmeticExprParser (Ok)
(Ln: 1, Col: 20): Leaving pexpression (Ok)
(Ln: 1, Col: 20): Leaving passignment (Ok)
(Ln: 1, Col: 20): Leaving pstatement (Ok)
(Ln: 1, Col: 20): Leaving pline (Ok)
(Ln: 1, Col: 20): Entering pline
(Ln: 1, Col: 20): Entering pstatement
(Ln: 1, Col: 20): Entering passignment
(Ln: 1, Col: 20): Leaving passignment (Error)
(Ln: 1, Col: 20): Entering pprint
(Ln: 1, Col: 20): Leaving pprint (Error)
(Ln: 1, Col: 20): Entering pread
(Ln: 1, Col: 20): Leaving pread (Error)
(Ln: 1, Col: 20): Leaving pstatement (Error)
(Ln: 1, Col: 20): Leaving pline (Error)
(Ln: 1, Col: 20): Leaving pcode (Ok)
[Assignment
   (Identifier "b",Arithmetic (Literal (Numeric 5.0),Sum,Literal (Numeric 7.0)))]

这可以帮助您找出问题，但更重要的是如何解决FParsec的未来问题。

FParsec仅在括号之间解析expr

1 个答案: