如何解决此错误:
无法在。中使用的表达式中使用聚合或子查询 GROUP BY子句的GROUP BY列表。
这是我的查询:
select Id, name,dayA,monthA,yearA,
sum(x) as x,
(select SUM(x) group by month) as total,
from table_A
group by Id,name,monthA,dAyA,yearA, SUM(x)
换句话说: 样本数据:
id name dayA monthA yearA x
===========================
1 name1 2 3 2016 4
2 name2 2 3 2016 3
3 name1 2 3 2016 2
预期结果:
id name dayA monthA yearA x total
===================================
1 name1 2 3 2016 4 6
2 name2 2 3 2016 3 3
3 name1 2 3 2016 2 6
提前致谢
答案 0 :(得分:0)
您的查询有更多问题。
hash2.each do |nestling|
nestling["activation_status"] = hash1[nestling["host"]]
end
,它来自同一张桌子,不太可能因为你的小组月没有提到。在查询中使用子查询时,您必须保证我只返回一条记录。
根据您的样本数据和预期结果......
(select SUM(x) group by month) as total
答案 1 :(得分:0)
可能这就是你想要的:
select table_A.*, TotalSums.total
from table_A
left join (select name, monthA, dayA, yearA, sum(x) as total from table_A group by name, monthA, dayA, yearA) as TotalSums
on table_A.name = TotalSums.name
and table_A.monthA = TotalSums.monthA
and table_A.dayA = TotalSums.dayA
and table_A.yearA = TotalSums.yearA
order by id
答案 2 :(得分:0)
我认为这就是你要找的东西
select Id, main.name,dayA,main.monthA,main.yearA,
sum(x) as x,
,max(total.total) as total
from table_A as main
join (select SUM(x) total ,name ,monthA,yearA from table_A group by name,monthA,yearA) as total
on main.name = total.name
and main.monthA = total.monthA
and main.yearA = total.yearA
group by Id,main.name,monthA,dAyA,yearA