我已经搜索了打开失败的解决方案：ENOENT（没有这样的文件或目录）错误但是已经厌倦了所有内容并且仍然无法正常工作。
我正在尝试将手机上的图片上传到我在服务器上创建的数据库。
06-01 15:59:32.631 25399-26074/com.example.vikhram.projectv E/Debug: error: /document/primary:Pictures/Pic0601_14Lat_65.6172057.jpeg: open failed: ENOENT (No such file or directory)
java.io.FileNotFoundException: /document/primary:Pictures/Pic0601_14Lat_65.6172057.jpeg: open failed: ENOENT (No such file or directory)
at libcore.io.IoBridge.open(IoBridge.java:452)
at java.io.FileInputStream.<init>(FileInputStream.java:76)
at com.example.vikhram.projectv.MainActivity$UploadFileAsync.doInBackground(MainActivity.java:406)
at com.example.vikhram.projectv.MainActivity$UploadFileAsync.doInBackground(MainActivity.java:375)
at android.os.AsyncTask$2.call(AsyncTask.java:295)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:234)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588)
at java.lang.Thread.run(Thread.java:818)
Caused by: android.system.ErrnoException: open failed: ENOENT (No such file or directory)
at libcore.io.Posix.open(Native Method)
at libcore.io.BlockGuardOs.open(BlockGuardOs.java:186)
at libcore.io.IoBridge.open(IoBridge.java:438)
at java.io.FileInputStream.<init>(FileInputStream.java:76)
at com.example.vikhram.projectv.MainActivity$UploadFileAsync.doInBackground(MainActivity.java:406)
at com.example.vikhram.projectv.MainActivity$UploadFileAsync.doInBackground(MainActivity.java:375)
at android.os.AsyncTask$2.call(AsyncTask.java:295)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:234)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588)
at java.lang.Thread.run(Thread.java:818)
06-01 15:59:32.631 25399-26074/com.example.vikhram.projectv E/AndroidRuntime: FATAL EXCEPTION: AsyncTask #1
Process: com.example.vikhram.projectv, PID: 25399
java.lang.RuntimeException: An error occurred while executing doInBackground()
at android.os.AsyncTask$3.done(AsyncTask.java:309)
at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:354)
at java.util.concurrent.FutureTask.setException(FutureTask.java:223)
at java.util.concurrent.FutureTask.run(FutureTask.java:242)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:234)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588)
at java.lang.Thread.run(Thread.java:818)
Caused by: java.lang.NullPointerException: Attempt to invoke virtual method 'java.io.InputStream java.net.HttpURLConnection.getInputStream()' on a null object reference
at com.example.vikhram.projectv.MainActivity$UploadFileAsync.doInBackground(MainActivity.java:459)
at com.example.vikhram.projectv.MainActivity$UploadFileAsync.doInBackground(MainActivity.java:375)
at android.os.AsyncTask$2.call(AsyncTask.java:295)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:234)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1113)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:588)
at java.lang.Thread.run(Thread.java:818)
这是我收到的错误消息。
这是我运行以检查getAbsolutePath（）;
的代码if (requestCode == READ_REQUEST_CODE && resultCode == RESULT_OK) {
// The document selected by the user won't be returned in the intent.
// Instead, a URI to that document will be contained in the return intent
// provided to this method as a parameter.
// Pull that URI using resultData.getData().
//Uri uri = null;
if (data != null) {
//super.onActivityResult(requestCode, resultCode, data);
Uri selectedImageURI = data.getData();
File myFile = new File(selectedImageURI.getPath());
//File myFile = new File(data.getData().toString());
//File imageFile = new File(getRealPathFromURI(selectedImageURI));
//new UploadFileAsync().execute(myFile.getAbsolutePath().toString());
new UploadFileAsync().execute(myFile.getAbsolutePath().toString());
//Log.i(TAG, "Uri: " + selectedImageURI.toString());
//showImage(uri);
}
}
答案 0 :(得分：0)
File myFile = new File(selectedImageURI.getPath());
如果您在getPath()上致电Uri，那么您做错了，除非Uri有file计划。您的Uri有一个content计划。不需要这样的Uri指向您能够读取的文件系统上的文件。
使用ContentResolver和openInputStream()在InputStream代表的内容上打开Uri。然后，将其用于UploadFileAsync所做的任何事情。
答案 1 :(得分：0)
确保首先创建父目录：
myFile.mkdirs();