Question

带有下拉字段的搜索栏的搜索查询是什么我必须从db中获取结果，该数据库有2个表
1. content_ref_table与字段
标题，描述，网址，course_id

course_ref_table with fields
course_id，课程

我必须在与所选课程相对应的标题和说明字段中搜索输入的文本

HTML

<input id ="search_bar" name= "search_bar"type="text" class="form-control"  placeholder="Search" >
            <span class="input-group-addon">

               <select class="form-control" name="selectVal">
                    <option value="course">Select Course</option>
                    <?php
                        $sql = mysqli_query($conn,"call courses_dropdown()");
                        while($row = mysqli_fetch_array($sql))
                        {   

                            echo "<option value='" . $row['courses'] ."'>" . $row['courses'] . "</option>";
                        }
                    ?> 
                </select>
            </span>  
<span class="input-group-addon">

                    <button type="submit">
                        <span class="glyphicon glyphicon-search"></span>
                    </button>  


                </span>
                </form>

php

<?php
 include 'includes/dbconfig.php';
 $search_term = $_GET['search_bar'];
  $select_course = $_GET['select_course'];
  $query = mysqli_query($conn,"SELECT * FROM content_ref_table WHERE            title LIKE  '%".$search_term."%' OR description LIKE  '%".$search_term."%'  LIMIT 0 , 30")
?>

Answer 1

在我看来，您的查询应该是这样的：

        $query = mysqli_query($conn,"SELECT * FROM content_ref_table,course_ref_table 
        WHERE title LIKE '%".$search_term."%' OR description LIKE '%".$search_term."%' 
        and content_ref_table.course_id = course_ref_table.course_id 
        and courses = '".$selected_course."' LIMIT 0 , 30")

使用like运算符搜索栏查询

1 个答案: