for (...) {
files.push(files[i]);
li_out.push({name : fileName, list_files : files});
}
如何按名称获取list_files数组?
var list_files_of_file3 = li_out[name == "file3" (?????)].list_files;
答案 0 :(得分:4)
var list_files_of_file3 = li_out.find(o => o.name === "file3").list_files;
// Variable names changed for DEMO purpose
var files = [];
for (var i = 0; i < 10; i++) {
files.push({
name: 'fileName ' + i,
list_files: 'something ' + i
});
}
var res = files.find(o => o.name === 'fileName 3').list_files;
console.log(res);
答案 1 :(得分:3)
如何按名称获取list_files数组?
使用filter
,尝试
var result = li_out.filter(function(item){ return item.name == "file3" });
是否也可以只返回匹配项的属性 而不是整个对象? (以下评论@MajidFouladpour)
获得结果后
var propertyNames = result.map(function(obj){ return obj.propertName; })