Question

我需要Oracle v11中CASE语句的帮助。我的公司使用TRAX Maintenance作为其软件，并使用QuickPrint构建“构建您自己的报告”。我正在尝试做一个小的CASE语句/函数，但只得到错误消息。任何人都可以帮忙吗？下面是完整的代码（非常简单），结果将返回1列，这是结果。

SELECT "ENGINEERING_ORDER"."EO" AS "EO",
       "ENGINEERING_ORDER"."EO_DESCRIPTION" AS "EO_DESCRIPTION",
       CASE,
       WHEN "ENGINEERING_ORDER"."SCHEDULE_HOURS"=0
   AND "ENGINEERING_ORDER"."SCHEDULE_CYCLES"=0 THEN "ENGINEERING_ORDER"."SCHEDULE_DAYS",
       WHEN "ENGINEERING_ORDER"."SCHEDULE_HOURS"=0
   AND "ENGINEERING_ORDER"."SCHEDULE_DAYS"=0 THEN "ENGINEERING_ORDER"."SCHEDULE_CYCLES",
       ELSE "ENGINEERING_ORDER"."SCHEDULE_HOURS",
       END
  FROM ENGINEERING_ORDER

我得到的错误是：

ORA-00923：未找到FROM关键字

ORA-00936：缺少表达

和其他人取决于您可以执行的其他方式CASE。

Answer 1

删除,和case之间的所有逗号（end），它们不应该在那里：

SELECT "ENGINEERING_ORDER"."EO" AS "EO",
       "ENGINEERING_ORDER"."EO_DESCRIPTION" AS "EO_DESCRIPTION",
       CASE
         WHEN "ENGINEERING_ORDER"."SCHEDULE_HOURS"=0
          AND "ENGINEERING_ORDER"."SCHEDULE_CYCLES"=0
         THEN "ENGINEERING_ORDER"."SCHEDULE_DAYS"
         WHEN "ENGINEERING_ORDER"."SCHEDULE_HOURS"=0
          AND "ENGINEERING_ORDER"."SCHEDULE_DAYS"=0 
         THEN "ENGINEERING_ORDER"."SCHEDULE_CYCLES"
         ELSE "ENGINEERING_ORDER"."SCHEDULE_HOURS"
       END
  FROM ENGINEERING_ORDER

案例陈述/职能

1 个答案: