Question

我有对象数组：

[{name:'test', lastname: 'test', gender:'f'},{name:'test1', lastname: 'test1', gender:'m'},{name:'test2', lastname: 'test2', gender:'m'}]

如何使用genger从数组中获取第一个（也是唯一一个）对象：'m'？

Answer 1

您可以使用find

var ar = [{name:'test', lastname: 'test', gender:'f'},{name:'test1', lastname: 'test1', gender:'m'},{name:'test2', lastname: 'test2', gender:'m'}];

var result = ar.find(function(e) {
  return e.gender == 'm';
});

console.log(result)

Answer 2

遍历数组并检查每次迭代中项是否有mFromDate.setOnTouchListener(new View.OnTouchListener() { @Override public boolean onTouch(View v, MotionEvent event) { final int actionPeformed = ev.getAction(); switch(actionPeformed){ case MotionEvent.ACTION_UP:{ mFromDate.setText(""); SetDateToDefault(1); //some method Bundle args = new Bundle(); args.putInt("day", day1); args.putInt("month", month1); args.putInt("year", year1); myDatePickerDialogFragment d1 = new myDatePickerDialogFragment(); d1.setArguments(args); d1.setOnDateSetListener(datePickerListener1); //onDateSet Listener that is not included in this question d1.show(getFragmentManager(), "days"); break; } return true; } });。可能看起来像这样：

gender == 'm'

Answer 3

您可以使用Array#find

如果数组中的元素满足提供的测试函数，则function first_male(data) { for (var i = 0; i < data.length; i++) { if (data[i].gender == 'm') { return data[i]; } } } var data = [ {name:'test', lastname: 'test', gender:'f'}, {name:'test1', lastname: 'test1', gender:'m'}, {name:'test2', lastname: 'test2', gender:'m'} ]; first_male(data); // Object {name: "test1", lastname: "test1", gender: "m"}方法在数组中返回find()。否则返回undefined。

＆＃13;

value

＆＃13;

如果不可用，请使用polyfill。或

＆＃13;

var array = [{name:'test', lastname: 'test', gender:'f'},{name:'test1', lastname: 'test1', gender:'m'},{name:'test2', lastname: 'test2', gender:'m'}];

console.log(array.find(a => a.gender ==='m'));

＆＃13;

Answer 4

你只需循环你的阵列。这里有一个非常相似的主题：Find a value in an array of objects in Javascript 当找到相应的对象时，返回指令将跳出循环。

如何获取具有特定属性的第一个且仅有一个对象？

4 个答案: