我尝试使用Postgresql wiki(https://wiki.postgresql.org/wiki/Retrieve_primary_key_columns)上建议的代码:
SELECT a.attname, format_type(a.atttypid, a.atttypmod) AS data_type
FROM pg_index i
JOIN pg_attribute a ON a.attrelid = i.indrelid
AND a.attnum = ANY(i.indkey)
WHERE i.indrelid = 'tablename'::regclass
AND i.indisprimary;
不幸的是,它似乎不适用于Redshift。我收到了这个错误:
ERROR: op ANY/ALL (array) requires array on right side
我做错了什么还是另一个红移异常?
非常感谢任何帮助。
答案 0 :(得分:5)
Redshift doesn't have the concept of primary keys http://docs.aws.amazon.com/redshift/latest/dg/t_Defining_constraints.html but identity attritube can be used to set uniqueness. (more info at http://docs.aws.amazon.com/redshift/latest/dg/r_CREATE_TABLE_NEW.html)
事实并非如此。
Redshift不会强制执行主键约束,但可以使用它们。它们在自动化数据管道或数据质量检查时非常有用。在设计星型模式时,redshift也建议使用它们,因为它们被查询优化器用作提示。 https://aws.amazon.com/blogs/big-data/optimizing-for-star-schemas-and-interleaved-sorting-on-amazon-redshift/
以下是获取表格主键的一种方法:
SELECT schemaname,tablename,replace(substr(ddl,POSITION('(' IN ddl)+1),')','' )primary_key FROM admin.v_generate_tbl_ddl WHERE schemaname =' schema' AND tablename =' table' AND upper(ddl)LIKE'%PRIMARY%';
视图的代码" admin.v_generate_tbl_ddl"在这里:https://github.com/awslabs/amazon-redshift-utils/tree/master/src/AdminViews
答案 1 :(得分:2)
您可以使用以下sql获取模式“ schemaname”中表“ tablename”的主键列表
SELECT
att.attname
FROM pg_index ind, pg_class cl, pg_attribute att
WHERE
cl.oid = 'schemaname."tablename"'::regclass
AND ind.indrelid = cl.oid
AND att.attrelid = cl.oid
and att.attnum = ANY(string_to_array(textin(int2vectorout(ind.indkey)), ' '))
and attnum > 0
AND ind.indisprimary
order by att.attnum;
答案 2 :(得分:1)
从INFORMATION_SCHEMA
进行操作非常容易:
select TC.column_name
from information_schema.table_constraints AS TC
inner join information_schema.key_column_usage AS KCU
on KCU.constraint_catalogue = TC.constraint_catalogue
and KCU.constraint_schema = TC.constraint_schema
and KCU.constraint_name = TC.constraint_name
where TC.constraint_type = 'PRIMARY KEY'
and TC.table_schema = '<my schema>'
and TC.table_name = '<my table>'
order by KCU.ordinal_position
是的,这适用于Redshift。
答案 3 :(得分:0)
在这个帮助下尝试: https://bitbucket.org/zzzeek/sqlalchemy/pull-request/6/sqlalchemy-to-support-postgresql-80/diff
SELECT attname column_name, attnotnull,
format_type(atttypid, atttypmod) as column_type, atttypmod,
i.indisprimary as primary_key,
col_description(attrelid, attnum) as description
FROM pg_attribute c
LEFT OUTER JOIN pg_index i
ON c.attrelid = i.indrelid AND i.indisprimary AND
c.attnum = ANY(string_to_array(textin(int2vectorout(i.indkey)), ' '))
where c.attnum > 0 AND NOT c.attisdropped AND c.attrelid = :tableOid
order by attnum
答案 4 :(得分:0)
dsz的答案对我不起作用,但是非常接近! (必须更改“目录”的拼写,从key_column_usage中选择而不是table_constraints,然后再添加一个并添加到联接中)
这对我来说适用于redshift和MySQL。尚未明确尝试Postgres,但应该可以:
select KCU.table_schema, KCU.table_name, KCU.column_name
from information_schema.table_constraints AS TC
inner join information_schema.key_column_usage AS KCU
on KCU.constraint_catalog = TC.constraint_catalog
and KCU.constraint_schema = TC.constraint_schema
and KCU.table_name = TC.table_name
and KCU.constraint_name = TC.constraint_name
where TC.constraint_type = 'PRIMARY KEY'
and TC.table_schema = '<my schema>'
and TC.table_name = '<my table>'
order by KCU.ordinal_position;
答案 5 :(得分:0)
可悲的是,ISO标准information_schema
的观点并没有说明Redshift的全部情况。我怀疑约束information_schema.table_constraints
中未列出,因为在Redshift中没有强制执行约束。
但是有办法
AWS提供了带有许多管理工具,实用程序和视图的github存储库。 视图是here
其中一个视图是v_generate_tbl_ddl
此视图可以为您提供完整的DDL以重新创建表,包括指定Primary Key
。
我已经提取了视图的相关部分,它将为您提供主键。该视图的其他部分显示了如何获取dist键,sort键和其他有用的东西:
SELECT
c.oid::bigint AS table_id,
n.nspname AS schemaname,
c.relname AS tablename,
pg_get_constraintdef(con.oid)::character varying AS PRIMARYKEY /*AS ddl*/
FROM pg_constraint con
JOIN pg_class c ON c.relnamespace = con.connamespace AND c.oid = con.conrelid
JOIN pg_namespace n ON n.oid = c.relnamespace
WHERE c.relkind = 'r'::"char" AND pg_get_constraintdef(con.oid) !~~ 'FOREIGN KEY%'::text
答案 6 :(得分:-1)
Redshift不强制执行主键http://docs.aws.amazon.com/redshift/latest/dg/t_Defining_constraints.html的概念,但可以使用身份attritube来设置唯一性。 (更多信息请见http://docs.aws.amazon.com/redshift/latest/dg/r_CREATE_TABLE_NEW.html)
有关现有表的详细信息,您可以使用以下查询
select column_name, is_nullable, data_type, character_maximum_length
from information_schema.columns
where table_schema='schema_name'
and table_name='table_name'
order by ordinal_position