SELECT DISTINCT CONCAT('TOTAL NUMBER OF LEGS IN A TRIP NUMBER ', T1.TNUM, ' IS NOT EQUAL TO THE LARGEST NUMBER OF LEG IN THE TRIP') AS 'ERR'
FROM TRIPLEG T1
WHERE MAX(T1.LEGNUM) = (SELECT COUNT(T2.TNUM)
FROM TRIPLEG
WHERE T1.TNUM = T2.TNUM);
使用我的代码,我试图找到违反以下一致性约束的所有行程。 每次旅行的最后一站必须等于旅程中的腿总数“
CREATE TABLE TRIPLEG(
TNUM DECIMAL(10) NOT NULL,
LEGNUM DECIMAL(2) NOT NULL,
DEPARTURE VARCHAR(30) NOT NULL, DESTINATION VARCHAR(30) NOT NULL,
CONSTRAINT TRIPLEG_PKEY PRIMARY KEY (TNUM, LEGNUM),
CONSTRAINT TRIPLEG_UNIQUE UNIQUE(TNUM, DEPARTURE, DESTINATION),
CONSTRAINT TRIPLEG_FKEY1 FOREIGN KEY (TNUM) REFERENCES TRIP(TNUM) );
INSERT INTO TRIPLEG VALUES( 1, 1, 'Sydney', 'Melbourne');
INSERT INTO TRIPLEG VALUES( 1, 2, 'Melbourne', 'Hobart');
答案 0 :(得分:0)
尝试以下内容;)
SELECT DISTINCT CONCAT('TOTAL NUMBER OF LEGS IN A TRIP NUMBER ', T1.TNUM, ' IS NOT EQUAL TO THE LARGEST NUMBER OF LEG IN THE TRIP') AS 'ERR'
FROM TRIPLEG T1
GROUP BY T1.TNUM
HAVING COUNT(T1.TNUM) <> MAX(T1.LEGNUM)