Question

我有一个字符串如下：

Well, here we are.^2000 Ain't much to look at, is it?^2000 Came here on a Wednesday night once.^1000 It was actually pretty crowded.^1000 But on a Tuesday evening .^300 .^300 .^1000 I guess it's just you^1000 and me.^3000 Heh.

现在我想知道如何删除所有^以及^之后的数字，以便最终输出以下内容，

Well, here we are. Ain't much to look at, is it? Came here on a Wednesday night once. It was actually pretty crowded. But on a Tuesday evening . . . I guess it's just you and me. Heh.

Answer 1

使用此：

var res = str.replace( new RegExp("(\\^\\d+)","gm"), "");

str是字符串，正则表达式匹配^<number>，替换字符串为""。

Answer 2

正如我在评论中所说，你想要使用名为Regex的东西。

＆＃13;

$(document).ready(function() {

  var html = $('#start').html();

  var output = html.replace(/(\^\d{2,4})/g, '');

  $('#results').html(output);


});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="start">
  Well, here we are.^2000 Ain't much to look at, is it?^2000 Came here on a Wednesday night once.^1000 It was actually pretty crowded.^1000 But on a Tuesday evening .^300 .^300 .^1000 I guess it's just you^1000 and me.^3000 Heh.
</div>
<div id="results">
</div>

＆＃13;

如何从Javascript字符串中删除特定的“序列”？

2 个答案: