Question

在输出中，new_dollars始终显示美元数，因此我不知道如何解决问题。请帮我弄清问题是什么。

int main(void)
{
    int dollars, cents, count, new_dollars;

    for ( count = 1; count <= 10; ++count){
        printf ("Enter dollars: ");
        scanf ("%i", &dollars);

        printf ("Enter cents: ");
        scanf ("%i", &cents);

        if ( cents >= 100 ){
            cents = cents % 100;
            new_dollars = dollars + cents / 100;
            printf ("%i\n", new_dollars);
            printf ("$%i.%2i\n\n", new_dollars, cents);
        }
        else {        
            printf ("$%i.%2i\n\n", dollars, cents);
        }
    }

    return 0;
}

Answer 1

评论者对整数除法是正确的。试试这个，它有两行进行交换计算的顺序，所以cents在需要它时仍然会有一个有用的值：

int main(void)
{
    int dollars, cents, count, new_dollars;

    for ( count = 1; count <= 10; ++count){
        printf ("Enter dollars: ");
        scanf ("%i", &dollars);

        printf ("Enter cents: ");
        scanf ("%i", &cents);

        if ( cents >= 100 ){
            new_dollars = dollars + cents / 100;
            cents = cents % 100;
            printf ("%i\n", new_dollars);
            printf ("$%i.%2i\n\n", new_dollars, cents);
        }
        else {        
            printf ("$%i.%2i\n\n", dollars, cents);
        }
    }

    return 0;
}

Answer 2

将“int new_dollars”转换为“float new_dollars”;
new_dollars =（浮动）美元+（浮动）美分/ 100;
printf（“$％。2f \ n”，new_dollars）;

＆＃34; new_dollars =美元+美分/ 100＆＃34;没变

2 个答案: